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Confusing Force function |
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| May13-10, 11:34 AM | #1 |
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Confusing Force function
1. The problem statement, all variables and given/known data
The force on a particle is directed along an x axis and given by [tex] F = F_0(\frac {x}{x_0} -1) [/tex]. Find the work done by the force in moving the particle from x = 0 to [tex] x = 2x_0 [/tex] 2. Relevant equations F=ma, W=Fd, etc. 3. The attempt at a solution I don't even know how to interpret that function. Does the [tex] x_0 [/tex] mean the initial position? Does [tex] F_0 [/tex] mean the initial force? I'm so confused. Any help would be appreciated. |
| May13-10, 12:15 PM | #2 |
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Hi DrummingAtom!
![]() (try using the X2 tag just above the Reply box ) …a "0" subscript always means a constant (usually the value at t = 0). ![]() (oh … except in relativity, where x0 means time! )
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| May13-10, 07:32 PM | #3 |
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I'm still confused on this one. So, if x0 F0 are constants then how would the graph of this function look? Because they want you to graph F(x) before integrating. I mean what do you pick for your constant in a situation like this? I know it's going to be a linear function.
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| May13-10, 08:19 PM | #4 |
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Confusing Force function0....x0...2x0...3x0... Now when you consider your graph's labels, you are integrating from 0 to 2x0, as the problem specifies! The y-axis is F. So where does F0 fit into your graph? I'll let you do that. |
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