If the clamped spring is dissolved in acid what becomes of its potential energy?

Click For Summary
SUMMARY

The discussion centers on the fate of potential energy stored in a compressed metal spring when it is dissolved in acid. Participants conclude that as the spring dissolves, its structural integrity fails, converting potential energy into kinetic energy as fragments disperse. This kinetic energy is ultimately transformed into heat energy, heating the acid, with minimal energy contributing to chemical reactions. The conversation also explores how mechanical energy can convert to chemical energy under strain, emphasizing the conservation of energy principles throughout the process.

PREREQUISITES
  • Understanding of potential and kinetic energy principles
  • Knowledge of electrochemical potential and corrosion processes
  • Familiarity with energy conservation laws in physical systems
  • Basic concepts of fluid dynamics, including laminar flow and turbulence
NEXT STEPS
  • Research the principles of energy conversion in mechanical systems
  • Explore the effects of strain on electrochemical reactions
  • Learn about the dynamics of turbulence versus laminar flow in fluids
  • Investigate the thermodynamics of chemical reactions under varying conditions
USEFUL FOR

Students of physics, engineers working with mechanical systems, chemists studying corrosion, and anyone interested in energy transformation processes.

PrakashPhy
Messages
35
Reaction score
0
If a compressible metal spring is compressed it achieves potential energy. But if the spring is dissolved in acid at its clamped state where does the stored potential energy go? Or what becomes of its potential energy.

Help me please.
 
Physics news on Phys.org
I think what would happen is that as the spring dissolved, eventually it would lose its structural integrity and the pieces of the spring would fly apart. The moving pieces would have kinetic energy equal to the stored potential energy of the spring. The pieces would then be stopped by friction in the acid, so ultimately all of the stored potential energy would go into heating up the acid.
 
A piece of metal under strain has a different electrochemical potential than an identical piece of unstrained metal. So that leads to slightly faster corrosion with higher currents and greater heating of the electrolyte.
 
phyzguy said:
I think what would happen is that as the spring dissolved, eventually it would lose its structural integrity and the pieces of the spring would fly apart. The moving pieces would have kinetic energy equal to the stored potential energy of the spring. The pieces would then be stopped by friction in the acid, so ultimately all of the stored potential energy would go into heating up the acid.

there you go its true.
the spring would first at most probably the point with greatest stress(midpoint) and then PE "stored" woul go inot heat,sound, and KE which is dissipated most of the PE is lost barely any is used for the reaction.
 
Thank you for your support. I somehow got it.
 
What if the spring was encapsulated in some sort of container that would prevent it from expanding in any direction - but this container was unaffected by the acid in question - even though it had holes in it to allow the acid to reach the spring?
 
Still its simple, since the spring is not stretched it will begin to dissolve as a whole rupturing arbitrarily, and slowy, because the energy if the system is maintained constant, there being no external parameters involved (as an assumption). so the spring will dissolve but rupturing very slowly so that change in KE=0 to maintain the condition you presented.
 
vaibhav1803 said:
Still its simple, since the spring is not stretched it will begin to dissolve as a whole rupturing arbitrarily, and slowy, because the energy if the system is maintained constant, there being no external parameters involved (as an assumption). so the spring will dissolve but rupturing very slowly so that change in KE=0 to maintain the condition you presented.

But if the spring volume has no room to expand, what happens to the kinetic energy stored as potential as it dissolves?
 
I answered that in post 3. Even if the spring does not break there is extra energy given to the electrolyte by a material corroding under strain.
 
  • #10
DaleSpam said:
I answered that in post 3. Even if the spring does not break there is extra energy given to the electrolyte by a material corroding under strain.

So the compression of the spring contributes to the total chemical potential of the reactive substances? Mechanical energy can simply become chemical energy because the reaction is taking place under strain?
 
  • #11
Yes. Even without the spring breaking.
 
  • #12
DaleSpam said:
Yes. Even without the spring breaking.

Are you sure the mechanical energy of the spring wouldn't create turbulence by pressing against the sides of the container while breaking apart inside? I don't think that mechanical energy can be converted into chemical energy except by changing parameters of the reaction such as temperature and pressure of the system.
 
  • #13
brainstorm said:
Are you sure the mechanical energy of the spring wouldn't create turbulence by pressing against the sides of the container while breaking apart inside?
Certainly it would, but this does not answer the conservation of energy question alone. As soon as any of the spring is dissolved the spring constant is reduced and therefore the mechanical potential energy is reduced. If the spring breaks only this reduced amuont of energy is recovered. You cannot explain the conservation only by the spring breaking.

brainstorm said:
I don't think that mechanical energy can be converted into chemical energy except by changing parameters of the reaction such as temperature and pressure of the system.
And changing temperature and pressure can cause a chemical reaction to shift equilibrium thereby storing chemical potential energy.
 
  • #14
DaleSpam said:
Certainly it would, but this does not answer the conservation of energy question alone. As soon as any of the spring is dissolved the spring constant is reduced and therefore the mechanical potential energy is reduced. If the spring breaks only this reduced amuont of energy is recovered. You cannot explain the conservation only by the spring breaking.
I would think the amount of wave-energy dispersed as turbulence would be equal to the amount potential in the compressed spring. The spring wouldn't appear to expand because it was incapsulated, but while dissolving it would vibrate, and the vibrations would travel through the container and into the surrounding liquid. The only way it would raise the pressure or temperature of the system is if the system was completely insulated, in which case I would guess the waves would become heat since both are KE.

And changing temperature and pressure can cause a chemical reaction to shift equilibrium thereby storing chemical potential energy.
How would that be relevant?
 
  • #15
brainstorm said:
I would think the amount of wave-energy dispersed as turbulence would be equal to the amount potential in the compressed spring. The spring wouldn't appear to expand because it was incapsulated, but while dissolving it would vibrate, and the vibrations would travel through the container and into the surrounding liquid. The only way it would raise the pressure or temperature of the system is if the system was completely insulated, in which case I would guess the waves would become heat since both are KE.
Sorry, I didn't realize you were still talking about th "encapsulated spring" scenario. In that case there would be no turbulence at all. A mechanical failure of the spring would turn the remaining mechanical potential energy into mechanical waves which would heat up the electrolyte, but again, you cannot account for all of the energy unless you consider the chemical energy.

brainstorm said:
How would that be relevant?
I was just providing a counter example to your suggestion that mechanical energy cannot be converted into chemical energy. That was wrong, chemical energy can be converted into mechanical energy and vice versa.
 
  • #16
DaleSpam said:
Sorry, I didn't realize you were still talking about th "encapsulated spring" scenario.
What scenario were you addressing then?
In that case there would be no turbulence at all. A mechanical failure of the spring would turn the remaining mechanical potential energy into mechanical waves which would heat up the electrolyte, but again, you cannot account for all of the energy unless you consider the chemical energy.
What other form does mechanical energy in a liquid take except turbulence? How would mechanical energy immediately become heat, without first becoming waves/turbulence in the liquid?

I was just providing a counter example to your suggestion that mechanical energy cannot be converted into chemical energy. That was wrong, chemical energy can be converted into mechanical energy and vice versa.
Any form of energy can be converted into any other form. The issue is what route it takes.
 
  • #17
the crux here is that there will be not net change in the system+surroundings energy content,the following transforms occur______
PE---->KE...under strain
PE/KE----> chemical energy(very small part) + heat(non-frictional+frictional)...under strain/after rupture respectively.
a part of non frictional heat is lost directly to the surrounding and a part heats the spring substance up and so is a pat of frictional heat
HEAT---> chemical energy the kinetics of the reaction are disturbed.
did i miss anything out..?
*all energy changes are subject o various coefficients hence most of the energy is use to cause a temperature change.
 
  • #18
brainstorm said:
What scenario were you addressing then?
The original one. The compressed spring in a corrosive liquid (no spring encapsulation). In that scenario when the spring fails the pieces will go shooting around inside the liquid and there will likely be turbulent flow.

In the scenario with an encapsulated spring the encapsulation prevents the pieces from shooting around the liquid, so there will be waves and probably friction, but probably not turbulence.

brainstorm said:
What other form does mechanical energy in a liquid take except turbulence? How would mechanical energy immediately become heat, without first becoming waves/turbulence in the liquid?
Both mechanical waves and laminar flow are other forms of mechanical energy in a fluid that can dissipate into heat without ever becoming turbulent. The word turbulence refers to a specific regime of flow.
 
  • #19
DaleSpam said:
Both mechanical waves and laminar flow are other forms of mechanical energy in a fluid that can dissipate into heat without ever becoming turbulent. The word turbulence refers to a specific regime of flow.

I didn't know of a more general word to refer to wave energy in a fluid at a super-molecular level.
 
  • #20
Sorry, i forgot the turbulence.
please stop complicating the picture, the guy's got it in the first few threads.
 
  • #21
vaibhav1803 said:
Sorry, i forgot the turbulence.
please stop complicating the picture, the guy's got it in the first few threads.

The OP was a silly trick question anyway. It was a game to see if people would think about energy so abstractly that they would think that it is literally contained in the metal of the spring the same as chemical potential energy is contained in the configuration of molecules. I just took a santa clause story and put jet engines on the sleigh, so to speak.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 45 ·
2
Replies
45
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
6
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
11K