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Volume of Solids of Revolution |
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| Jun16-10, 03:12 PM | #1 |
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Volume of Solids of Revolution
Find the volume of the solid st,
1. y=cos x , y= 0 in [0,pi] ; Rotated around x=1 2. I am slightly confused, I see that the area will double around twice so I can just use the left half of the curve. I am just not sure how to do so. |
| Jun16-10, 04:57 PM | #2 |
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Mentor
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Are you sure that you copied this problem correctly. The line x = 1 does not divide the region between y = cosx and y = 0 into two equal halves, so rotating it around the line x = 1 makes a complicated volume of revolution. Could it be that you're supposed to rotate the region around the line y = 1?
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| Jun16-10, 05:23 PM | #3 |
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Yes, not 2 equal halves but the rotation around the x=1 axis would cover the right hand side of the curve in rotation and double over so cant we ignore that piece?
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| Jun16-10, 06:31 PM | #4 |
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Mentor
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Volume of Solids of Revolution
No, I don't think so. The part of the region under y = cosx on [0, 1] would cover the part on [1, pi/2], so I suppose you could ignore that part. The part of the curve on [pi/2, pi] is below the x-axis. The part above [0, 1] is above the x-axis. This is a very unusual problem.
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