How can you determine the net force of a bottle

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Homework Help Overview

The discussion revolves around determining the net force acting on a bottle containing fluid under pressure, specifically at 2 atm, and how the geometry of openings affects this calculation. The subject area includes fluid dynamics and pressure concepts.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the application of Bernoulli's equation and the relationship between pressure and force. Questions arise regarding the calculation of pressure in relation to the bottle's openings and whether to consider the combined area of multiple openings.

Discussion Status

The discussion is active, with participants offering insights into pressure calculations and the implications of multiple openings. There is an ongoing exploration of how external pressure might influence the net force, indicating a productive exchange of ideas without a definitive consensus.

Contextual Notes

Participants are considering the effects of different assumptions about the geometry of the openings and the external pressure conditions, which may impact their calculations.

Gmaximus
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How can you determine the net force of a bottle who's contents are kept under 2 atm of pressure, and it has a 1 cm opening for example?

a1v1=a2v2 doesn't seem to apply, and the flowrate=dav doesn't seem to either. I suspect it is bernoulli's equation, but I am unsure.

I know P=F/A, but how do you find the pressure? is it simply the pressure difference?
 
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Also, if the bottle has two openings facing in the same direction, how does that work? Do you add the area of the two holes and use that for area, or is it two separate cases?
 
Pressure is defined as "force divided by area" or P= F/A so F= P*A. You are given that the pressure is 2 atmospheres and the fluid is coming out an area of pi cm2 (I am assuming that the "1 cm" hole has radius 1 cm. If it is diameter= 1 cm, then the area is pi/4 cm2).

Yes, if you have two holes of area A1 and A2, then that is the same as 1 hole of area A1+ A2.
 
Does the outside pressure matter?
 

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