p75213
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a= d/t^2. Therefore is it the case that the acceleration involved in stair climbing is the distance of the slope divided by the time^2? Where does gravity fit into it?
The discussion centers on the relationship between acceleration, distance, and time squared in the context of stair climbing. The formula a = d/t² is incorrectly applied; the correct formula for uniform acceleration from rest is a = 2d/T². Participants clarify that most individuals do not climb stairs with increasing speed, and gravity is not a direct factor in this specific analysis of stair climbing acceleration.
PREREQUISITESStudents of physics, fitness trainers, and anyone interested in understanding the mechanics of human movement and acceleration during stair climbing.
Where did you get that relationship? For uniform acceleration starting from rest, the acceleration would be: 2d/T^2.p75213 said:a= d/t^2.
No. Most folks don't climb stairs with increasing speed.Therefore is it the case that the acceleration involved in stair climbing is the distance of the slope divided by the time^2?
It doesn't. Gravity is just one of the forces acting on the stair climber.Where does gravity fit into it?