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distance formula

 
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Sep6-04, 01:48 PM   #1
 

distance formula


Yah, easy I know, but I got a little confused. Okay, here's the problem:
Find the distance between the points to the nearest tenth. J(2,-1) K(2,5) Here's what I did. d=√(2-2)^2+(5-(-1)^2 (the ^2 means squared) √(2-2)^2=0 so I'm left with √(5-(-1)^2= √(6)^2= √36=6 Ok, so how did I do? I wasn't sure if what I did was right, I think so, but I just needed to make sure. Thanks.
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Sep6-04, 02:21 PM   #2
 
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Your solution is correct.
Sep6-04, 02:37 PM   #3
 
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In fact, in that case, since the x coordinates of (2,-1) and (2,5) are the same so the distance is just the distance between -1 and 5 on a number line: 5-(-1)= 6.
Sep6-04, 02:49 PM   #4
 

distance formula


Oh, yah I never thought about that. Heh, that would have saved some time, I'll remember that! Thanks to both of you.
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