Distance Formula: Find JK Distance to Nearest Tenth

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Discussion Overview

The discussion revolves around calculating the distance between two points, J(2,-1) and K(2,5), using the distance formula. The focus is on confirming the correctness of the calculations and understanding the concept behind the distance between points in a Cartesian plane.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents their calculation of the distance using the formula, expressing confusion about the correctness of their approach.
  • Another participant confirms that the solution provided is correct.
  • A third participant notes that since the x-coordinates are the same, the distance can be simplified to the difference between the y-coordinates, which is 5 - (-1) = 6.
  • The original poster acknowledges this simpler approach and expresses appreciation for the insights shared.

Areas of Agreement / Disagreement

Participants generally agree on the correctness of the distance calculation, with no significant disagreement noted. However, there is a recognition of different approaches to arrive at the same result.

xowe
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Yah, easy I know, but I got a little confused. Okay, here's the problem:
Find the distance between the points to the nearest tenth. J(2,-1) K(2,5) Here's what I did. d=√(2-2)^2+(5-(-1)^2 (the ^2 means squared) √(2-2)^2=0 so I'm left with √(5-(-1)^2= √(6)^2= √36=6 Ok, so how did I do? I wasn't sure if what I did was right, I think so, but I just needed to make sure. Thanks.
 
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Your solution is correct.
 
In fact, in that case, since the x coordinates of (2,-1) and (2,5) are the same so the distance is just the distance between -1 and 5 on a number line: 5-(-1)= 6.
 
Oh, yah I never thought about that. Heh, that would have saved some time, I'll remember that! Thanks to both of you.
 

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