midpoint

xowe

Erm, I have another problem. This question confused me, I'm not sure how to do it. Help would be apprecaited. Thanks
The midpoint of line QS is the origin. Point Q is located in Quadrant II. What quadrant contains point S?
Same with this one.
M(5,12) is the midpoint of line AB. The coordinates of point A are (2,6). What are the coordinates of point B?

Muzza

Draw a picture. Take a point Q in the second quadrant, and draw a line from Q to the origin. Into which quadrant can you extend the line (so that it is still straight)? Now, which quadrant must S lie in?

xowe

Quadrent 4 I think. Ok, I think I get it. Thanks

HallsofIvy

In general, the midpoint of the line segment from (x₀,y₀) to (x₁,y₁) is the "average" of the two: ((x₀+x₁)/2, (y₀+y₁)/2).

In this case you are told that the midpoint of the line segment from A:(2,6) to the point B (call its coordinates (x,y)) is (0,0). That is (2+ x)/2= 0 and (6+y)/2= 0. It should be easy to see that B is (-2, -6).

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xowe	midpoint Erm, I have another problem. This question confused me, I'm not sure how to do it. Help would be apprecaited. Thanks The midpoint of line QS is the origin. Point Q is located in Quadrant II. What quadrant contains point S? Same with this one. M(5,12) is the midpoint of line AB. The coordinates of point A are (2,6). What are the coordinates of point B?

Muzza	Draw a picture. Take a point Q in the second quadrant, and draw a line from Q to the origin. Into which quadrant can you extend the line (so that it is still straight)? Now, which quadrant must S lie in?

HallsofIvy Recognitions: Gold Member Science Advisor Staff Emeritus	midpoint In general, the midpoint of the line segment from (x₀,y₀) to (x₁,y₁) is the "average" of the two: ((x₀+x₁)/2, (y₀+y₁)/2). In this case you are told that the midpoint of the line segment from A:(2,6) to the point B (call its coordinates (x,y)) is (0,0). That is (2+ x)/2= 0 and (6+y)/2= 0. It should be easy to see that B is (-2, -6).