What is the power output of the sun?

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Discussion Overview

The discussion revolves around calculating the power output of the sun based on the mass-energy equivalence principle, specifically using the equation E = mc². Participants explore how to apply this equation to determine the energy conversion from mass in the sun.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that approximately 4 x 10^9 kg of matter is converted into energy each second in the sun and seeks help in finding the power output.
  • Another participant suggests using the equation E = mc² to convert mass to energy, indicating that power is energy per unit time.
  • A later post reiterates the use of E = mc² and provides a formula for power as P = Δe/Δt = Δmc²/Δt, introducing the rate of mass conversion.
  • One participant humorously acknowledges a mistake in their earlier post, indicating a casual tone in the discussion.
  • A participant shares a vivid analogy from a lecture to illustrate the concept of mass conversion, emphasizing the scale of the energy involved.

Areas of Agreement / Disagreement

Participants generally agree on the use of E = mc² for calculating the power output, but there is no consensus on the specific steps or calculations involved, as some participants express confusion or seek clarification.

Contextual Notes

Some participants express uncertainty about the correct application of the equations and the calculations needed to arrive at the power output, indicating potential gaps in understanding or assumptions about the problem.

Who May Find This Useful

This discussion may be useful for students or individuals interested in understanding the application of mass-energy equivalence in astrophysics or those seeking help with similar physics problems.

fishboy39
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I have a physics problem that I am stuck on: Approximately 4 x 10^9 kg of matter is converted into energy each second in the sun. Find the power output of the sun. I know the answer is 3.6 x 10^26 W I just can't figure out how to get the correct equation and numbers. Any help would be appreciated. Thanks
 
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The relevant equation is
[tex]E = mc^2[/tex]
 
fishboy39 said:
I have a physics problem that I am stuck on: Approximately 4 x 10^9 kg of matter is converted into energy each second in the sun. Find the power output of the sun. I know the answer is 3.6 x 10^26 W I just can't figure out how to get the correct equation and numbers. Any help would be appreciated. Thanks

Use [ tex ] E = mc^2 [ /tex] to convert the mass to energy, then power is just energy per unit time.
 
Thanks! I knew it was something easy!
 
...why not e=mc^2?
 
LOL sorry must've left the window on too long... haha
 
[tex]e=mc^2[/tex]
[tex]P=\frac{\Delta e}{\Delta t}=\frac{\Delta mc^2}{\Delta t}[/tex]
Given [tex]\frac{\Delta m}{\Delta t}= 4*10^9 kg/s[/tex]
[tex]c=3.00*10^8 m/s[/tex]
 
This reminds me of a lecture my (lively) optics professor gave.
He asked us to just imagine four billion kilograms of matter being
converted every second.
"Suppose you would throw 700 g brick up into outer space every second. (he freely demonstrates what it would be like).
Now imagine all the people in the world doing that." It's amazing :bugeye:
 

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