Help Needed for Grade 11 Physics Assignment & Interference Pattern Question

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The discussion revolves around a Grade 11 physics assignment involving a converging mirror and the calculation of image height. The user applied the mirror formula \(1/f = 1/Di + 1/Do\) and derived an image distance (Di) of 2.56 cm, leading to an image height (Hi) of -0.32 cm. The calculations are correct, but the negative sign indicates that the image is inverted. Additionally, the user inquired about interference patterns, specifically whether the second nodal line at 50 degrees corresponds to n=1 or n=1/2.

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antiflag403
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Hey all,
Grade 11 physics assignment due tmrw and I am having some trouble. Any help would be appreciated. So here it is:

A candle of height 4.8 cm is placed 38.6 cm in front of a converging mirror with curvature 30.2 cm. What is the height of the image?

Heres what I have:

1/f = 1/Di + 1/ Do so... 1/15.1 = 1/Di + 1/38.6 so Di=2.56

then...

Hi/Ho = -Di/Do so... Hi/4.8 = -2.56/38.6 so Hi=-.32

where:
Ho= Height of object (candle)
Do= Distance of object
Di= Distance of image
Hi= Height of image
f=focus (which i have calculated to be 15.1)

The answer i get is -.32cm which doesn't seem right to me. Am i doing something wrong? Missing something??

As well... a totally unrelated question- When looking at interference patterns of water through 2 openings, if the second nodal line is formed at an angle of 50 degrees, will n=1 or n=1/2?

Thanks for any help!
 
Last edited:
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Are you unsure of the sign or the magnitude of your answer? Or both?
 
Try solving the image problem backwards.
 

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