Solving the Steffan-Boltzman Law: Transfer of Power from Left to Right Plate

  • Context: Graduate 
  • Thread starter Thread starter shyta
  • Start date Start date
  • Tags Tags
    Law
Click For Summary

Discussion Overview

The discussion revolves around the application of the Stefan-Boltzmann law to a scenario involving two plates with different temperatures and emissivities. Participants explore the net power transfer from a hotter left plate to a cooler right plate, addressing the complexities of emissivity and radiation absorption.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant presents the formula for net power radiated from the left plate to the right plate as Pnet flow from left to right = kA (e1T14e2 - e2T24), expressing confusion about its derivation.
  • Another participant agrees with the net power transfer expression but questions the use of emissivity e2 instead of e1.
  • A participant challenges the understanding of emissivity, asking for clarification on which emissivity should be used in the context of the two plates.
  • Further discussion includes the need to consider both the radiation emitted by the left plate and the fraction absorbed by the right plate, highlighting the directional nature of radiation transfer.
  • One participant expresses uncertainty about the necessity of multiplying by the fraction absorbed by the right plate when calculating net transfer.
  • Another participant requests more detailed explanations of the original poster's understanding and work, emphasizing the importance of clarity in communication.
  • There is a suggestion to simplify the problem by choosing a specific value for e2 to facilitate calculations.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct approach to calculating the net power transfer, with multiple competing views on the role of emissivity and the correct application of the Stefan-Boltzmann law.

Contextual Notes

Participants express uncertainty regarding the definitions and roles of emissivity in the context of the problem, as well as the implications of directional radiation transfer. There are unresolved questions about the calculations and assumptions made in the proposed formulas.

shyta
Messages
56
Reaction score
0
Hi guys, I need help on my concept on the steffan's law.

I understand that for a grey body sphere confined within a blackbody spherical shell, the general formula for the net power radiated from inner sphere should be

Prad = kAe(T4-Tsurr4)
where k=stefan Boltzmann's constant

However recently, I was given a question which made me really confused.
For the case where 2 plates are separated by a gap and the left plate has a higher temp, T1 and emissivity, e1 = 1, as compared to the right plate having T2 and emissivity e2. Then the net rate of power transferred from the left to the right is?

Prad by left plate = kAe1T14
Prad by right plate = kAe2T24
which all of it is absorbed by the left plate since emissivity is 1

then fraction absorbed by right plate is e2
and fraction reflected by right plate is 1-e2(all absorbed by the left plate)


Pnet flow from left to right = kA (e1T14e2 - e2T24)

But how??
 
Science news on Phys.org
anyone? :(
 
shyta said:
Pnet flow from left to right = kA (e1T14e2 - e2T24)

But how??

I agree, net power transfer is [itex]Ake_2(T_1^4-T_2^4)[/itex]. What's the problem?
 
why is it e_2 and not e_1?
 
Why is which e_2? Why wouldn't it be e_2?
It would really help if you explained in detail how much you do understand. Which parts did you work out yourself, and which parts have you simply copied from somewhere else? Please show your own work more clearly. Explain with more detail exactly what it is that you don't understand. And is this part of a homework question?
 
No it's not part of a homework.

isn't the emissivity used supposed to be the one of the object, as in for the 2 plates situation, the emissivity of the left plate (e=1?)

what i am confused about is why there is a need to multiply by the fraction absorbed by the right plate when finding the net transfer?
 
If you want my help, it would be great if you helped me more to help you. Are you saying that you yourself figured out everything except the second last line of your original post, but that second last line you took from a book and do not know how to obtain yourself?

Some components to consider:
- the radiation from 2 to 1.
- the fraction of the radiation from 1 that is absorbed by 2.
Note these are in opposite directions. Do you know how to combine these into the "net"?

Alternatively:
- the initial radiation from 2, in one direction.
- all the radiation from 1, in the other direction.
- the part, of the radiation originally from 1, that reflects back from 2 to 1 again, in the first direction.
This should also give the same answer.
 
yes i did take it from something like a book.

Prad by left plate = kAe1(T14-T24)


then we have to consider the fraction reflected by the right plate which got absorbed back by the left plate which is 1-e2

which is the part I'm confused about
 
What is "like a book"? Please cite your source.

What does "Prad" mean?

Can you calculate exactly how much power, in Watts, the right plate absorbs? (And exactly how much power reflects back at the left plate?)

Is it easier to solve the problem if I choose e_2 = 0.25 ?
 

Similar threads

Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 152 ·
6
Replies
152
Views
12K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
11K