Derivative of f: Finding the Derivative of \sqrt{x}(2x-7)

[Dantes]

Find the derivative of f when :

$$\sqrt{x}(2x-7)$$

When put into product rule form (following (f '*g) + (f*g') )

$$(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)$$

Just started today making sure I am on the right track.

 

[justinbaker]

i am pretty sure this is actually the answer when in product rule

$$(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)$$

 

[Dantes]

i am pretty sure this is actually the answer when in product rule

$$(\frac{1}{2}x^\frac{-1}{2})\ast(2x+7) + \sqrt{x}(2)$$

Ahh yes...My fault doubled it twice.. thanks.

 

[Dantes]

hmm my fundamentals are screwed up, I forgot what happens here for the most part. with the fraction exponents and the radicals.

Factor the $$(\frac{1}{2}x^\frac{-1}{2})$$ into the $$(2x+7)$$ ?