What Is the Angle of Elevation for a 1.00-Meter Track with 1.86 cm Blocks?

[dg_5021]

hey can someone help me solve this problem. How do find the angle of elevation? Is there a formula for it? please help



Problem-
Two calibrated elevation blocks have a combined thickness of 1.86 cm. Find the angle of elevation of the 1.00-meter long track for this situation.

 

[Tide]

Draw a picture. Can you find the right triangle? :-)

 

[M98Ranger]

Finding the angle of elevation can be done using trigonometry. The formula for finding the angle of elevation is tanθ = opposite/adjacent, where θ is the angle of elevation, opposite is the height of the object, and adjacent is the distance from the object to the observer. In this problem, the height of the object is 1.86 cm (the combined thickness of the elevation blocks) and the distance from the object to the observer is 1.00 meter (the length of the track). Plugging these values into the formula, we get tanθ = 1.86/100. Solving for θ, we get θ = arctan(1.86/100) = 1.07 degrees. Therefore, the angle of elevation for this situation is approximately 1.07 degrees. I hope this helps!