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Goldbach Partitions

 
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Oct28-10, 07:14 AM   #1
 

Goldbach Partitions


Intuitive reasoning has led me to develop a simple approximation, which contains factors different from those used in well knoen formulas. Numerically, "my" formula delivers results, which are almost as accurate, as Hardy-Littlewood`s with the Shah-Wilson correction.

Thanks in advance for any comments
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File Type: pdf Goldbach.pdf (217.6 KB, 40 views)
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Oct28-10, 09:12 AM   #2
 
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The formula (2) has a typo or is otherwise ill-posed. I trust from the parenthetical comment that the intent is

[tex]\frac12\pi(n)\prod_{3<p<\sqrt n}\frac{p-2}{p-1}[/tex]

Your approximations in (2.1) are off by a factor of about 2.245838. (I'll let you figure out where this came from.) This causes the derivation of (2) to be wrong.

Asymptotically, the ratio of g_alt/g_HL is not 1 but about 1.123. The first factor is 1 + O(1/log n), the third factor is 1 + o(1), and looks to drop off like 1 + O(1/log^2 n). The second factor is where the trouble comes from.
Oct30-10, 07:54 AM   #3
 
Thank you indeed, CRGreathouse, for signalling this error.

Using Merten's Theorem, I find, that g_alt must be divided by 2*exp(-gamma)=1,122918967...,
with gamma=0,577215664901... being Euler-Mascheroni's constant.

Then, g_alt will be asymptotically equivalent to g_HL

I'm now working on correcting the derivation of (2)

Best Regards - Marchal
Dec1-10, 04:29 AM   #4
 

Goldbach Partitions


Here is a revised version of my article.
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File Type: pdf Goldbach2.pdf (657.5 KB, 6 views)
Dec1-10, 08:57 PM   #5
 
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I wrote several paragraphs of response but the forum ate it, grr. In short: There are about two dozen errors in the first few pages, but they're mostly minor and correctable. By page 3 you use notations that are not only nonstandard but for which I can't even find any valid interpretation.

Unfortunately your use of ≈ rather than, say, ~ makes your statements non-testable (and even non-falsifiable in a Poperian sense).
Dec2-10, 10:44 AM   #6
 
Dear CBGreathouse

Thanks for reviewing my text with so much attention!.

In standard notation I should write

n[tex]\neq[/tex]0 (modp) (equation 2a)

q[tex]\neq[/tex]0 (modp) and q[tex]\neq[/tex]n (modp) (equation 2.2.1)

I changed the equivalence symbols, as you suggested (see attachment).
Dec2-10, 10:51 AM   #7
 
Did I miss uploading the file Goldbach3?
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File Type: pdf Goldbach3.pdf (661.2 KB, 7 views)
Dec2-10, 12:39 PM   #8
 
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1.2 still has issues. It's C_2 not C_HL and the "<= infinity" should be dropped. (There are rare cases where you want to write "< infinity" for clarity, but this isn't one and certainly "<= infinity" is just wrong.)

2a confuses me; what's the definition of g_alt? If this is supposed to be the definition you need = not ~ (or one of the defined-as symbols, if you prefer).

For congruences you need ≡ ≢ not = ≠ .

Have to go now; might look at p. 3 ff. later.
Dec5-10, 11:07 AM   #9
 
I still worked on page 3. Here it comes with corrections.
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File Type: pdf page 3.pdf (273.9 KB, 1 views)
Dec6-10, 05:36 AM   #10
 
Please ignore my last message. Here comes page3-improved version.
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File Type: pdf page 3 improved version.pdf (282.1 KB, 8 views)
Dec6-10, 09:00 AM   #11
 
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2.2.2 is the first questionable part: you claim that one obtains asymptotic equivalence. (You mark it an estimate, but then write ~.) This heuristic has been well-known for hundreds of years, but a proof is lacking. This is what you'd expect if the primes fell 'randomly', but it's not clear that they do in an appropriate fashion.
Dec8-10, 07:54 AM   #12
 
Thanks, Greg. I fully agree. Besides, I suspect my deduction to be substantially erronous. I'll need some time to clarify the matter.
Until then
Marchal
Feb10-11, 07:49 AM   #13
 
Here I am again! For correct formula & deduction, see APPENDIX attached.
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File Type: pdf APPENDIX.pdf (396.8 KB, 2 views)
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