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Goldbach Partitions |
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| Oct28-10, 07:14 AM | #1 |
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Goldbach Partitions
Intuitive reasoning has led me to develop a simple approximation, which contains factors different from those used in well knoen formulas. Numerically, "my" formula delivers results, which are almost as accurate, as Hardy-Littlewood`s with the Shah-Wilson correction.
Thanks in advance for any comments |
| Oct28-10, 09:12 AM | #2 |
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The formula (2) has a typo or is otherwise ill-posed. I trust from the parenthetical comment that the intent is
[tex]\frac12\pi(n)\prod_{3<p<\sqrt n}\frac{p-2}{p-1}[/tex] Your approximations in (2.1) are off by a factor of about 2.245838. (I'll let you figure out where this came from.) This causes the derivation of (2) to be wrong. Asymptotically, the ratio of g_alt/g_HL is not 1 but about 1.123. The first factor is 1 + O(1/log n), the third factor is 1 + o(1), and looks to drop off like 1 + O(1/log^2 n). The second factor is where the trouble comes from. |
| Oct30-10, 07:54 AM | #3 |
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Thank you indeed, CRGreathouse, for signalling this error.
Using Merten's Theorem, I find, that g_alt must be divided by 2*exp(-gamma)=1,122918967..., with gamma=0,577215664901... being Euler-Mascheroni's constant. Then, g_alt will be asymptotically equivalent to g_HL I'm now working on correcting the derivation of (2) Best Regards - Marchal |
| Dec1-10, 04:29 AM | #4 |
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Goldbach Partitions
Here is a revised version of my article.
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| Dec1-10, 08:57 PM | #5 |
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I wrote several paragraphs of response but the forum ate it, grr. In short: There are about two dozen errors in the first few pages, but they're mostly minor and correctable. By page 3 you use notations that are not only nonstandard but for which I can't even find any valid interpretation.
Unfortunately your use of ≈ rather than, say, ~ makes your statements non-testable (and even non-falsifiable in a Poperian sense). |
| Dec2-10, 10:44 AM | #6 |
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Dear CBGreathouse
Thanks for reviewing my text with so much attention!. In standard notation I should write n[tex]\neq[/tex]0 (modp) (equation 2a) q[tex]\neq[/tex]0 (modp) and q[tex]\neq[/tex]n (modp) (equation 2.2.1) I changed the equivalence symbols, as you suggested (see attachment). |
| Dec2-10, 10:51 AM | #7 |
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Did I miss uploading the file Goldbach3?
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| Dec2-10, 12:39 PM | #8 |
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1.2 still has issues. It's C_2 not C_HL and the "<= infinity" should be dropped. (There are rare cases where you want to write "< infinity" for clarity, but this isn't one and certainly "<= infinity" is just wrong.)
2a confuses me; what's the definition of g_alt? If this is supposed to be the definition you need = not ~ (or one of the defined-as symbols, if you prefer). For congruences you need ≡ ≢ not = ≠ . Have to go now; might look at p. 3 ff. later. |
| Dec5-10, 11:07 AM | #9 |
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I still worked on page 3. Here it comes with corrections.
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| Dec6-10, 05:36 AM | #10 |
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Please ignore my last message. Here comes page3-improved version.
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| Dec6-10, 09:00 AM | #11 |
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2.2.2 is the first questionable part: you claim that one obtains asymptotic equivalence. (You mark it an estimate, but then write ~.) This heuristic has been well-known for hundreds of years, but a proof is lacking. This is what you'd expect if the primes fell 'randomly', but it's not clear that they do in an appropriate fashion.
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| Dec8-10, 07:54 AM | #12 |
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Thanks, Greg. I fully agree. Besides, I suspect my deduction to be substantially erronous. I'll need some time to clarify the matter.
Until then Marchal |
| Feb10-11, 07:49 AM | #13 |
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Here I am again! For correct formula & deduction, see APPENDIX attached.
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