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Stretching a Brass Wire |
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| Nov14-10, 02:47 PM | #1 |
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Stretching a Brass Wire
1. The Problem...
A brass wire is to withstand a tensile force of 350 N without breaking. What minimum diameter must the wire have? Given Quantity: Young's modulus for brass = 9.0 * 10^10 2. What I Thought I Needed to Solve It... Young's modulus = Tensile strength/Tensile strain Stress = Force/cross section area Strain = distance stretched/initial length 3. I only know 2 of the 5 variables; how much force will be applied and Young's modulus. I'm not sure where to go without knowing the stretch or length of the wire. |
| Dec1-10, 07:22 PM | #2 |
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Is it even solvable? Or is there something painfully obvious that I'm missing?
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| Dec1-10, 08:12 PM | #3 |
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Young's modulus is a measure of stiffness: how difficult it is to achieve elastic, reversible deformation. You need to look up the strength of brass: the ultimate tensile strength that it can withstand without breaking.
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| Dec1-10, 08:40 PM | #4 |
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Stretching a Brass WireEDIT: oohh, way too late with this response. |
| Dec4-10, 12:33 PM | #5 |
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I wasn't provided a graph, or a figure for the tensile strength of Brass. If I was to use tensile strength rather than Young's modulus, would the same equation apply?
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