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Finding the constants in a general solution

 
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Nov20-10, 09:27 PM   #1
 

Finding the constants in a general solution


I have

x(t) = C(sub1) sin(16t) + C(sub2) cos(16t)

Given: initial position x(0) = 1/6
so:
1/6 = C(sub1) sin(0) + C(sub2) cos(0)
1/6 = C(sub2)

but how do i find C(sub1)? im not given initial velocity
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Nov20-10, 09:36 PM   #2
 
Well you have:

C1*sin(16t)+(1/6)cos(16t)=0

It's possible to isolate C1 here with simple algebra. What do you get when you try this?
Nov20-10, 09:45 PM   #3
 
No, you don't have enough information to determine [tex]C_1[/tex].
Nov20-10, 09:50 PM   #4
 

Finding the constants in a general solution


C1 = (-1/6)*(cos(16t)/sin(16t))

im a allowed to do that (set the eq. to zero)?

also, the book answer is x(t) = (1/6)*cos(16t)
so C1 must be zero, but i cannot solve for C1(cant plug in initial position 0 because that would be dividing by zero.
Nov20-10, 09:59 PM   #5
 
C1 is not a constant if it depends on 1/tan(16t).
Besides, that comes from assuming that x(t) is zero everywhere, which you did not state in the problem.

You have only presented one equation to extract information from: x(0)=1/6. It is not possible to determine both constants from one piece of information. Any value for [tex]C_1[/tex] is consistent with the information you have given us. Is there more?
Nov20-10, 10:14 PM   #6
 
sooo sorry. I've been reading the problem over and over (it's actually a mass on spring problem). It uses the term "from rest", meaning initial velocity is 0. Now when i solve for the constants i get

0 = 16C1 and C1 = 0

Wow, an hour wasted because i missed that part
Nov20-10, 10:34 PM   #7
 
Good start on any problem to count the number of unknowns and see what information you need to hunt 'em down :-)
Nov21-10, 08:38 AM   #8
 
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