Learn How to Solve this Math Problem with Basic Knowledge | Need Help Now!

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Homework Help Overview

The discussion revolves around a mathematical problem involving an equation related to time and velocity, likely within the context of physics or algebra. The original poster expresses difficulty with a specific aspect of the problem after missing classes.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore various algebraic manipulations of the equation, with some suggesting squaring both sides and others providing different forms of the equation. There are attempts to clarify the setup and assumptions regarding the variables involved.

Discussion Status

Participants are actively engaging with the problem, offering different interpretations and algebraic approaches. Some guidance has been provided, but there is no explicit consensus on the final form of the solution. The discussion remains open with various lines of reasoning being explored.

Contextual Notes

There is mention of the original poster's missed classes, which may contribute to their uncertainty. Additionally, one participant notes the possibility of mistakes in their calculations, indicating a need for verification.

nyu
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This isn't homework, but I missed the last few classes so I'm in dire need of help. I was given a quiz today, amazingly - I was able to do all of it with just basic math knowledge...except one >_> And it's bothering me that I don't understand it >_>

Here is the problem:

[URL][PLAIN]http://www.fall3n.com/homework/solvev.gif[/PLAIN]

[PLAIN]http://www.fall3n.com/homework/solvev.gif[/PLAIN]

If anybody could explain it thoroughly, it'd be appreciated ;)
Thank you!
 
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I assume that's a radical in the denominator.

Multiply both sides by the radical, square both sides then solve for v.
 
Ok um I am assuming the equation is [tex]t=T/(1-(V^2/c^2))[/tex]

therefore

t = T*v^2
-------
v^2-c^2
therefore
v=-c sqroot(t)
-----------
sqroot(t-T)
 
Alright I kind of cheated and used the calculator last time
but I solved by hand and got the following

[tex]t=\frac{T}{{1 - v^2/c^2}}[/tex]

[tex]t=\frac{Tc^2}{{c^2-v^2}}[/tex]
[tex]c^2-v^2=\frac{Tc^2}{{t}}[/tex]
[tex]-v^2=\frac{Tc^2}{{t}}-c^2[/tex]
[tex]v^2=\frac{-Tc^2}{{t}}+\frac{c^2t}{{t}}[/tex]
[tex]v^2=\frac{tc^2-Tc^2}{{t}}[/tex]
[tex]v^2=\frac{c^2(t-T)}{{t}}[/tex]
[tex]v=+ or - \frac{c\sqrt{(t-T)}}{{t}}[/tex]
 
I am very tired though and could have made a mistake please check your answers with someone else or have someone confirm mine
 
Yes, Tom McCurdy's last response:

[tex]v=+ or - \frac{c\sqrt{(t-T)}}{{t}}[/tex]

is correct.
 
YES... not only did i do some algerbra but I learned latex
 

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