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Proof- triangles |
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| Sep30-04, 08:57 PM | #1 |
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Proof- triangles
ok, i'm in first year coolege and we're doing some review from highschool work.. but i can't for the life of me remember how to do one of these questions and i can't seem to get past this one part or at least figure out how to prove that it is what i think it is.
it's gonna be a bit trickier, cuz i can't insert a picture, but i guess that isn't of the most importance anyways. alright you have triangle ABC. side AB=4 units side AC=7 units the line CD extends for 3 units towards point B, the distance between point B an D is unknown and is what needs to be found the Angle BCD is = angle DAC here's what i've tried to do so far... i've tried to fold the 2 triangles in half across the line AD, which lines up the two sides AB and AC, with the line AC extending 3 units futher then line AB. I'm still trying to follow this train of reasoning.. but so far with little success, i don't really know what to do next, but i think it helps somehow : ) next... I tried extending the common side between the two triangles, line AD, far enough so that i can draw a new line, 7 units long, from point C, i'll call the intersection point E. The problem arises when i can't prove that the new triangle DEC is the same as triangle ADC. I CAN prove that it is proportional to triangle ABD, but that doesn't help me, because i only know that the side CE is 7 units, the Side DC is 3 units, and i don't know if i can prove that the angle DEC is equal to the angle DAC... which means i can't prove that the line DE is a continuation of the line AD... hence i'm lost. thx for the help in advance.. hey, kewl... just found the attacthment thing... i'll go draw a picture and then post :) |
| Sep30-04, 09:14 PM | #2 |
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Hint: angle bisector theorem.
Hope that helps! |
| Sep30-04, 11:10 PM | #3 |
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nope, doesn't help... i looked it up on the net, and got this "The angle bisector of an angle in a triangle divides the opposite side in the same ratio as the sides adjacent to the angle."
so the angle bisector is line AD, and the adjacent and opposiye side are? i can't assume ANY right angles... and all the other stuff i found on this theorem had something to do with area of a triangle, which i can't do either, because i don't have enough info to find that yet... a bit more of a hint is needed
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| Oct1-04, 01:02 PM | #4 |
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Proof- trianglesLet me paraphrase the theorem for the triangle you've got : Simply, it says that CD/BD = AC/AB. Now go back and understand what the theorem is trying to say. |
| Oct1-04, 03:09 PM | #5 |
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so, 3/x=4/7
3/x=1.75 x=1.75*3 x=5.25 huh, i had gotten that number before... just couldn't prove that it was the right number... now i can with that theorem thx a lot guys :))))) |
| Oct5-04, 01:04 PM | #6 |
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oops... i mean 3/7=x/4
so 3/7=.429 .429x4=1.7 units therefore BD=1.7 |
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