Solve RC Circuit: Find Capacitor Value

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SUMMARY

The discussion focuses on calculating the value of a capacitor connected to a 2Kohm resistor across a 100Hz power line. The impedance of the capacitor is defined as 1/(jωC), where ω is the angular frequency. Using Ohm's law, the capacitive reactance (Xc) is substituted for resistance, leading to the formula Xc = 1/(2πfC). Given that Xc equals 2000 ohms and the frequency is 100Hz, the capacitance can be determined through rearranging the formula to solve for C.

PREREQUISITES
  • Understanding of Ohm's Law
  • Familiarity with capacitive reactance (Xc)
  • Basic knowledge of AC circuit analysis
  • Proficiency in algebraic manipulation of formulas
NEXT STEPS
  • Calculate the capacitance using the formula C = 1/(2πfXc)
  • Explore the concept of impedance in AC circuits
  • Study the effects of frequency on capacitive reactance
  • Learn about the applications of capacitors in filtering and timing circuits
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Electrical engineering students, hobbyists working with AC circuits, and professionals involved in circuit design and analysis will benefit from this discussion.

gregbellows
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Hi,

I am stuck on a question to work out the value of a capacitor,

The Question is:
A capacitor and a 2Kohm resistor pass the same current when each is separately connected across a 100Hz power line.
What is the value of the capacitor?
 
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The impedance of a capacitor is

[tex]\frac{1}{j \omega C}[/tex].

The resistance of the capacitor at 100 Hz is just the real part of that impedance (this is the hard part). Use Ohm's law (V = ZI) to solve for the capacitance.

- Warren

- Warren
 
ohms law shows us that e = i times r, when considering capacitance and frequencies, we substitute r with Xc (capacitive reactance). when a frequency is applied to a capacitor it allows current flow at a rate of ;
Xc=1/[2 * pie(3.14) * f (freq.) *c(farrads)]
***this is the formula for the impedence of a capacitor.
Xc= 2000, f= 100:
therfore C= ? you do the math
 
Last edited:

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