Finding the initial velocity of a thrown object caught at a certain height

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Homework Help Overview

The discussion revolves around two physics problems involving motion: one concerning a car decelerating to a stop and the other involving a thrown rocket being caught at a certain height. The subject area includes kinematics and the equations of motion.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the equations needed to solve for distance in the context of the car's deceleration and the initial velocity of the thrown rocket. There are questions about the interpretation of symbols and the application of formulas.

Discussion Status

Some participants have provided equations and initial calculations, while others express uncertainty about their understanding of the symbols and the overall problem-solving process. There is acknowledgment of correct calculations, but no consensus on the final outcomes for the rocket problem.

Contextual Notes

One participant mentions that the problems are for practice rather than homework, indicating a focus on understanding rather than completing assignments. There is also a note of a significant time gap since the last physics problem was encountered, which may affect participants' confidence in their problem-solving skills.

Jake M
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A car is traveling along a road at 35.1 meters/second(m/s). All of a sudden the navigator yells "Stop! The driver quickly applies the brakes at an acceleration of -2m/s/s (meters per second squared) and comes to a stop.

How much distance it take to stop the vehicle?

My question is what equations to use in solving this problem.
Thanks for any hep in advance.
 
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Givens:
Vi=35.1 m/s
Vf=0 m/s
a= -2 m/s/s
d= ?

THis is the formula you can use to solve for distance (d):
vf^2 = Vi^2 + 2ad
 
Hi there PM,
thanks for the info. It's been about 20years since I've had a physics problem to solve. This isn't home work or anything but rather practice for an up coming Rocketry event. Can you show me how to solve for this? The symbols have me abit confused. Also another word problem that came up was the following:
A man is standing at a launch site. The rocket doesn't liftoff. Frustrated s/he throws it straight up with a speed of 12.42 m/s. It is caught on the way down at a point 5.0 meters above where it was thrown, by a fellow rocketeer on the second floor, who doesn't want to see any harm come ot this wonderful rocket. The first man wants to figure out how fast the rocket was going when it was caught.
Again thanks for all your help, really rusty with this right now.
 
Sorry PM, For the first equation my answer was 308.00250000000005
Am I on the right track?
many thanks again,
Jake.
 
yes that looks correct to me.
 
A man is standing at a launch site. The rocket doesn't liftoff. Frustrated s/he throws it straight up with a speed of 12.42 m/s. It is caught on the way down at a point 5.0 meters above where it was thrown, by a fellow rocketeer on the second floor, who doesn't want to see any harm come ot this wonderful rocket. The first man wants to figure out how fast the rocket was going when it was caught.
Again thanks for all your help, really rusty with this right now.

Any help on this one?
 

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