insane prob


by allergic
Tags: insane, prob
allergic
allergic is offline
#1
Oct5-04, 12:44 AM
P: 11
alright, so i have this problem, and i must have gone wrong somewhere, because i am now lost.
the problem is this:
you have a canal that makes a right angle turn. the width of the canal for the incoming leg is a, and the width for the outgoing is b. what is the longest narrow barge that can be moved around the turn?

we were given this hint:
let x be the angle formed by a line segment touching the inside corner and terminating at the outside walls of the canal; here the angle is formed by the line segment and the outside wall of the leg of width b. the length of the line segment is
L(x)=a sec x + b csc x
as x approaches zero or pi/2, the length of this line segment approaches positive infinity. the maximum length of a barge that can make the turn is the minimum value of L(x).

so this is what i did:
i said L'(x) = a sec x tan x - b csc x cot x and set that = 0
I ended up getting b/a = tan ^3 (x) and then, x = tan ^-1 [(b/a)^(1/3)]
that could be where i screwed up, but who knows. i then wanted to plug that all back in to the L(x) equation. but there i am stuck, because if i make (b/a)^(1/3) = p, i end up with L = a sec (cot p) + b csc (cot p) and i have NO idea where to go from there.
anyone got any ideas?
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Tide
Tide is offline
#2
Oct5-04, 01:12 AM
Sci Advisor
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P: 3,149
Don't forget that

[tex]a^2 + b^2 = L^2[/tex]
HallsofIvy
HallsofIvy is offline
#3
Oct5-04, 06:49 AM
Math
Emeritus
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Thanks
PF Gold
P: 38,885
Quote Quote by Tide
Don't forget that

[tex]a^2 + b^2 = L^2[/tex]
Why would that be true? a and b are not legs of a right triangle in this problem.

allergic (to what? trig?), your result that tan3x= b/a looks good to me. That is, of course, the same as saying tan x= b1/3/a1/3.

Now, imagine a right triangle set up with legs of length b1/3 (opposite angle x) and a1/3 (next to angle x). The hypotenuse is given by [itex]\sqrt{b^{2/3}+a^{2/3}}[/itex]. You can calculate sec x and csc x from that.

allergic
allergic is offline
#4
Oct5-04, 09:30 AM
P: 11

insane prob


ah-ha! that would be it. i always forget that kinda stuff.
thanks
Tide
Tide is offline
#5
Oct5-04, 12:17 PM
Sci Advisor
HW Helper
P: 3,149
Halls,

Sorry about that - I was looking at the condition for the ship to just fit the corner then misread my own sketch!


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