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Uniform continuity, cauchy sequences |
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| Jan15-11, 01:00 PM | #1 |
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Uniform continuity, cauchy sequences
1. The problem statement, all variables and given/known data
If f:S->Rm is uniformly continuous on S, and {xk} is Cauchy in S show that {f(xk)} is also cauchy. 2. Relevant equations 3. The attempt at a solution Since f is uniformly continuous, [tex]\forall[/tex][tex]\epsilon[/tex]>0, [tex]\exists[/tex][tex]\delta[/tex]>0: [tex]\forall[/tex]x, y ∈ S, |x-y| < [tex]\delta[/tex] => |f(x)-f(y)| < [tex]\epsilon[/tex] So I said that let x, y be sequences, {xn} and {xp} Since {xn} is Cauchy, [tex]\forall[/tex][tex]\epsilon[/tex]>0, [tex]\exists[/tex]N : [tex]\forall[/tex]n,p [tex]\geq[/tex] N , |xn-xp| < [tex]\epsilon[/tex] Then using the fact that f is uniformly continuous, |f(xn)-f(xp)| < [tex]\epsilon[/tex] I don't think this is right.. am I allowed to replace those x's and f(x)'s with the sequences for example? |
| Jan15-11, 02:10 PM | #2 |
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Recognitions:
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Yes, basically, that's OK. You only need to be aware of the fact that for exactly this δ > 0 you found N (using the fact that (xn) is Cauchy).
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