# Real parameter given complex variable modulus

by jubbles
Tags: complex, modulus, ratio, real
 P: 1 1. The problem statement, all variables and given/known data Suppose z is complex number with |z| = 1 (also assume that z is not 1 + 0*i) Let z = a + b*i where a and b are real numbers. Find a real parameter, t, such that z = (t-i)/(t+i), where i = sqrt(-1) 2. Relevant equations |z| = sqrt(a^2+b^2) 3. The attempt at a solution Since we are given |z| = 1, this implies that a^2 + b^2 = (a+b*i)*(a-b*i) = 1. Also, (t-i)/(t+i) can be expressed as [1/(t^2+1)]*[(t^2-1)+(-2*t)*i]. Despite my efforts, I end up at two deadends: I reduce an equation to a tautology like 0 = 0 or I reduce to an expression for t that involves i (thereby making t imaginary instead of real). Any help is greatly appreciated.
 HW Helper P: 1,584 First off find c(t),d(t) such that: $$c(t)+d(t)i=\frac{t-i}{t+i}$$ Then use the fact that c(t)^{2}+d(t)^{2}=1
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P: 7,076
 Quote by jubbles 3. The attempt at a solution Since we are given |z| = 1, this implies that a^2 + b^2 = (a+b*i)*(a-b*i) = 1. Also, (t-i)/(t+i) can be expressed as [1/(t^2+1)]*[(t^2-1)+(-2*t)*i]. Despite my efforts, I end up at two deadends: I reduce an equation to a tautology like 0 = 0 or I reduce to an expression for t that involves i (thereby making t imaginary instead of real). Any help is greatly appreciated.
Write

$$\frac{1}{t^2+1}\,\left[(t^2-1)+(-2t)i\right]$$

as

$$\frac{(t^2-1)}{t^2+1}-\frac{2t}{t^2+1}\,i\right]$$

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