Position of Block After Applied Force of 2.8N

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Homework Help Overview

The discussion revolves around a physics problem involving a block on a frictionless surface connected to a spring. The block is subjected to an applied force of 2.8 N, and participants are exploring the implications of this force on the block's position when it comes to a stop.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between the applied force and the spring force, with one suggesting the need for a force diagram. There is also mention of using the spring force formula, and questions arise regarding the sign of the force and the direction of movement.

Discussion Status

The discussion is active, with participants questioning assumptions about the problem setup and the calculations involved. Some guidance has been offered regarding the need to check the direction of forces and the application of the spring force formula.

Contextual Notes

There is an indication that the problem may have been misposted in the forum, and participants are reminded to adhere to the homework help section guidelines. Additionally, there is a focus on ensuring the correct interpretation of the problem's parameters, such as directionality.

mochabcha
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I have a problem I need help with:
A block lies on a horizontal frictionless surface and is attached to the free end of the spring, with a spring constant of 35 N/m. Initially, the spring is at its relaxed length and the block is stationary at position x = 0. Then an applied force with a constant magnitude of 2.8 N pulls the block in the positive direction of the x axis, stretching the spring until the block stops.
Assume that the stopping point is reached. What is the position of the block?
 
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What's the problem with the problem ? Draw a force diagram. You know how to calculate the force due a stretched spring...do it.
 
I've tried the formula F(spring) = -kx and got -.08 but that's not the answer.

It seems to me when the mass stops the applied force will equal the spring force
 
next time try posting in the homework help section
 
And check your sign. Read what the question says about which direction (positive or negative x-direction) the block is pulled.
 

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