What is the Maximum Value of u(x,t) in the Given Region?

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SUMMARY

The maximum value of the function u(x,t) = -2xt - x² in the defined region {-2 ≤ x ≤ 2, 0 ≤ t ≤ 1} occurs at the point (x, t) = (-1, 1), yielding u(-1, 1) = 1. The critical point found at (0, 0) is a saddle point, as determined by evaluating the second derivatives. To find the absolute maximum, it is essential to evaluate the function along the boundaries of the specified region.

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I have u(x,t)=-2xt-x^2 find maximum in region {-2 ≤ x ≤ 2 , 0 ≤ t ≤ 1}

I believe to find the critical point first I have to take the partial derivative with respect to x and t and equate to zero.
Thus
Ux=-2t-2x = 0
Ut=-2x = 0

Thus the only critcal point I find is x=0, t=0.
But the maximum (answer at back of book) is x=-1, t=1 => u(-1,1)=1

Where did I go wrong?
 
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That's because (0, 0) is a saddle point (check the second derivatives!). You need to examine the absolute maximum of the function in the region.
 
Ok, got it. I forgot that then I need to evaluate along the boundaries of the region.
 

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