
#1
Feb811, 09:35 PM

P: 2

1. Vector A has a magnitude of 14 m and makes an angle of 26o with the positive x axis. Vector B also has a magnitude of 13 m and is directed along the negative x axis. Enter your answers in distance then angle(in degrees).
2. Find A + B Find A  B 3. 14cos(26)=12.6 x component for A 14sin(26)=6.14 y component for A 13 x component for B 0 y component for B A+B sqrt( (Ax+Bx)^2 + (Ay+By)^2 ) sqrt( (12.613)^2 + (6.14)^2 ) A+B=6.16 tan1(y/x) tan1(6.14/.4)=86.3* I haven't attempted AB yet. Tell me where I'm going wrong. Any help is appreciated. 



#2
Feb811, 09:45 PM

P: 264

in the arctan equation .4 should be .4, also why are you using 6.15 when the only vertical component is 6.14?




#3
Feb811, 09:51 PM

P: 2

thanks 


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