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Simplify math course workby Michael_Light
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#1
Feb1211, 09:16 PM

P: 117

1. The problem statement, all variables and given/known data
Simplify Please kindly show the working steps as well. ^^ Thanks. 2. Relevant equations 3. The attempt at a solution I tried but i have no idea on how to start... 


#2
Feb1211, 11:16 PM

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P: 3,562

I can't see what you posted. Can you write it here?



#4
Feb1311, 12:07 AM

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P: 3,562

Simplify math course work
Ok, by simplification I assume they mean rationalizing the denominator (getting rid of square roots in the denominator). Do you know about multiplying by the conjugate?



#5
Feb1311, 12:26 AM

P: 117




#6
Feb1311, 01:13 AM

HW Helper
P: 3,562

If you have something like [tex]\frac{1}{1+\sqrt{x}}[/tex] then you can get rid of any roots in the denominator (bottom part of the fraction) by multiplying by the conjugate [tex]1\sqrt{x}[/tex]
Basically, the conjugate of a+b is ab. When you multiply [tex]1+\sqrt{x}[/tex] by [tex]1\sqrt{x}[/tex] you get [tex]1x[/tex]. When you multiply ab by a+b you get [tex]a^2b^2[/tex] so you can see that if a and b are square roots, the square roots will vanish in the denominator. So multiplying by the top and the bottom will give you [tex]\frac{1}{1+\sqrt{x}}=\frac{(1\sqrt{x})}{(1+\sqrt{x})(1\sqrt{x})}=\frac{1\sqrt{x}}{1x}[/tex] That is what you call rationalizing the denominator. Now, for your question, the conjugate of [tex]\sqrt{1x^2}+\sqrt{1+x^2}[/tex] will be...? 


#7
Feb1311, 02:10 AM

P: 117




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