One question on conservation of mass and energy

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SUMMARY

The discussion focuses on the conservation of mass and energy in a relativistic context, specifically analyzing a Kaon decaying into two pions. The rest mass of the Kaon is 497.67 MeV/c², while each pion has a rest mass of 139.57 MeV/c². The equations governing momentum and energy conservation are established, including the Lorentz factor (G) for both the Kaon and the moving pion. The challenge lies in determining the kinetic energy of the Kaon and the energy of the moving pion without known velocities, emphasizing the necessity of relativistic principles in particle physics.

PREREQUISITES
  • Understanding of relativistic physics concepts, including Lorentz transformations
  • Familiarity with conservation laws in physics, specifically momentum and energy conservation
  • Knowledge of particle physics, particularly the properties of Kaons and pions
  • Ability to manipulate equations involving energy (E=mc²) and momentum
NEXT STEPS
  • Study the derivation and application of Lorentz transformations in particle decay scenarios
  • Learn how to calculate relativistic kinetic energy using the formula K = (γ - 1)mc²
  • Explore conservation of momentum in relativistic collisions and decays
  • Investigate experimental methods for measuring particle velocities in high-energy physics
USEFUL FOR

This discussion is beneficial for physicists, students of particle physics, and anyone interested in understanding relativistic effects in particle decay processes.

stunner5000pt
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with relativistic concepts in mind

A Kaon split into 2 pions, One pion is stationary and one is stil moving in the same direciton.

For Kaon rest mass = 497.67MeV/c^2
Pion = 139.57MeV/c^2

What is the kineric energy of the kaon and what is the energy of hte pion not at rest.

Since momentum is conserved

Let gamma = G

G1 Mk Vk = Gp Mp Vp

Also energy is conserved

Kk + Mk c^2 = Mp c^2 + Mp c^2 (G2 - 1)
Kk + Mkc^2 = G2 Mp c^2

Where Kk i the kinetic energy of the kaon and Mk is the mass of the kaon, Mp is the mass of pion, G2 is the lorentz factor of the pion in motion

I am stuck here however and i have no clue on how to proceed without velocities!
 
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With relativistic concepts in mind, the conservation of mass and energy can be described by the famous equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. This equation shows that mass and energy are interchangeable and one can be converted into the other. In the case of the Kaon splitting into two pions, the total mass of the system must remain constant, but the energy can be distributed between the two particles.

To determine the kinetic energy of the Kaon and the energy of the pion in motion, we can use the equations for conservation of momentum and energy in a relativistic system. The momentum of the system is conserved, so we can set up an equation with the initial momentum of the Kaon equal to the final momentum of the two pions.

Using the equation G1 Mk Vk = Gp Mp Vp, where G1 and Gp are the lorentz factors of the Kaon and pion respectively, we can solve for the velocity of the pion in motion (Vp). Once we have the velocity, we can use the equation for energy conservation, Kk + Mkc^2 = G2 Mp c^2, to solve for the kinetic energy of the Kaon (Kk) and the energy of the pion in motion (G2 Mp c^2).

Therefore, with the help of relativistic concepts and equations, we can determine the kinetic energy of the Kaon and the energy of the pion in motion in this scenario. This highlights the importance of considering relativistic effects in conservation laws, as they play a crucial role in understanding the behavior of particles at high speeds or energies.
 

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