Solving Collision Problem: Finding Speeds of Balls After Impact

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Homework Help Overview

The discussion revolves around a collision problem involving two identical balls, where one ball strikes the other at rest. The problem focuses on determining the speeds of both balls after the collision, given their initial conditions and the angles at which they move post-collision.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the conservation of momentum, questioning the correctness of their setup and how to solve the resulting equations. Some participants suggest methods for solving the equations, while others raise questions about the approach to combining results from the two equations.

Discussion Status

The discussion is active, with participants providing guidance on solving the equations and clarifying the relationship between the components. There is an exploration of different methods to approach the problem, but no consensus has been reached on the best way to combine the results.

Contextual Notes

Participants are navigating the constraints of the problem, including the need to consider both x and y components separately and the implications of vector magnitudes in their calculations.

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A ball moving with a speed of 15 m/s strikes an identical ball that is initially at rest. After the collision, the incoming ball has been deviated by deta1 = -41° from its original direction, and the struck ball moves off at deta2 = 24° from the original direction. What are the speeds of the two balls after the collision?

I set up these two equations:
initial momentum = final momentum

x component: v1(initial) = v1(final)*cos(-41) + v2(final)*cos(24)

y component: 0 = v1(final)*sin(-41) + v2(final)*cos(24)

Did I set up this right?
How would I solve these equations?
 
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You have two equations and two unknowns and the relationships are linear! It's easy to solve. For example, solve the 2nd equation for v1_final in terms of v2_final then substitute that result into the first equation which you can readily solve for v2_final -which, in turn, let's you explicitly determine v1_final.
 
These 2 equations are separate components (X and Y). I can just solve for the 2nd one and plug into the first? I thought I have to solve each one individually and then combine them to find the hypontenuse (V_final).
 
Well if you solve for each then you can add their squares and find the square root to find the magnitude of the vector!
 

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