How Strong is the Gravitational Pull Between Tom and Sally?

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Homework Help Overview

The problem involves calculating the gravitational attraction between two individuals, Tom and Sally, based on their masses and the distance separating them. It is set in a hypothetical scenario on a dance floor, with specific values provided for mass and gravitational constant.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the formula for gravitational force and attempt to apply it to the given masses and distance. Some question the phrasing of the problem, particularly regarding the visibility of Tom and the nature of the attraction Sally feels. Others explore the implications of gravitational attraction in everyday situations.

Discussion Status

There are varying interpretations of the problem, with some participants focusing on the calculation while others challenge the assumptions made in the scenario. Guidance has been offered regarding the nature of gravitational attraction and its perceptibility in this context, but no consensus has been reached.

Contextual Notes

Participants note the potential confusion in the problem's wording and the implications of gravitational attraction versus personal weight. There is also mention of the unrealistic nature of detecting such small gravitational forces in everyday life.

kimikims
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anyone know how to do this problem??

Tom has a mass of 65.7 kg and Sally has a
mass of 52.9 kg. Tom and Sally are standing 28.7 m apart on a massless dance foor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its magnitude. Assume both can be replaced by spherical masses and that G=6.67259 x 10^-11 Nm^2/kg^2.
Answer in units of N.
 
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Use

[tex]F = G\frac{m_{1}m_{2}}{d^2}[/tex]
 
So... would this be correct?

F= 6.67259 x 10^-11 [(65.7kg)(52.9kg) / (28.7)^2)]
 
kimikims said:
anyone know how to do this problem??

Tom has a mass of 65.7 kg and Sally has a
mass of 52.9 kg. Tom and Sally are standing 28.7 m apart on a massless dance foor. Sally looks up and she sees Tom. She feels an attraction. If the attraction is gravitation, find its magnitude. Assume both can be replaced by spherical masses and that G=6.67259 x 10^-11 Nm^2/kg^2.
Answer in units of N.

This question is phrased weird. If they are both standing on the dance floor, then she will not see Tom by looking up unless there's a mirror on the ceiling, which would be irrelivant to the problem anyway.

She feels an attraction. If the attraction is gravitation, find its magnitude.
This should be 9.81 m/s^2 in the down direction. Despite the massless floor, the Earth that the massless floor is on is still pulling with a magnitude of 9.81 m/s^2.

She will definitely feel the Earth's attraction. As far as the gravity exerted by Tom's mass, she definitely will not feel this attraction. The most sensitive equipment on Earth would not be able to detect Tom's presence by his gravity field, so Sally certainly can't feel Tom's gravitational attraction. This implies you don't have to compute anything.
 
No silly...she feels some attraction, not her own weight! We all feel our weight all the time, and we don't classify it as anything out of the ordinary. So why would she suddenly start paying attention to it? The question implies that she feels some gravitational attraction other than her attraction to the Earth (her weight). They want you to compute her gravitational attraction to Tom, just to drive home the point that everything made up of matter in the universe is gravitationally attracted to everything else, but the effects in everyday situations (such as between people) are miniscule. Yeah ok, so she would never actually be able to feel said attraction, but you're being too literal...get into the spirit of the question! Didn't you ever get these silly problems in high school..."ooh, I think there's some "attraction" between Tom and Sally...can you compute its magnitude?", says the physics teacher with a ridiculous grin on his face, thinking himself terribly witty. :rolleyes:

As for the looking up part, they don't mean "straight up"! The question is trying to be melodramatic...she was glancing down distracted for a second (for whatever reason), and when she looked up again, there he was.

A more important question comes from this phrase: "If the attraction is gravitation, find its magnitude." What if it isn't? I think there's actually some chemistry going on here... :wink:
 
Last edited:
"As for the looking up part, they don't mean "straight up"! The question is trying to be melodramatic...she was glancing down distracted for a second (for whatever reason), and when she looked up again, there he was."
Isn't the usual sequence:
Suddenly catches sight of TOM, flustered, looks down, then helplessly, is drawn to look at him again??:confused:
 

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