|Mar9-11, 03:00 PM||#1|
so I have 1/(n-2). I have that n>max(epsilon+2,1). I need to get 1/(n-2) < epsilon. I know that 1/(n-2)<1/(epsilon+2-2)=1/epsilon. but 1/epsilon is not always less than epsilon. can you see any errors?
|Mar11-11, 01:38 PM||#2|
Your question is unclear.
|Mar11-11, 01:49 PM||#3|
1/(n - 2) < epsilon <==> n - 2 > 1/epsilon, making the reasonable assumptions that n > 2 and epsilon > 0.
If epsilon is small and positive, 1/epsilon is generally larger than epsilon.
|epsilon, inequalities, proof|
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