# Relationship b/w Connectedness and Homeomorphisms

by rekovu
Tags: b or w, connectedness, homeomorphisms, relationship
P: 1
I'm using Real Mathematical Analysis by Pugh to supplement my analysis class, and the book has been clear thus far, but I've been stuck for days on a concept I've had a hard time understanding.

Just for reference, here is how a homeomorphism is defined:

 Let M and N be metric spaces. If f: M->N is a bijection and f is continuous and the in verse bijection f-1:N->M is also continuous is also continuous then f is a homeomorphism and M, N are homeomorphic.
And here is how connectedness is defined:

 Let M be a metric space. If M has a proper clopen subset A, M is disconnected. For there is a separation of M into proper, disjoint clopen subsets. M is connected if it is not disconnected - it contains no proper clopen subset.
I understand that M connected and M homeomorphic to N implies N connected, and that M connected, f:M->N continuous, and f onto implies N connected. However, what I don't understand are examples such as the following:

 Example The union of two disjoint closed intervals is not homeomorphic to a single interval. One set is disconnected and the other is connected.
 Example The closed interval [a,b] is not homeomorphic to the circle S1. for removal of a point x in (a,b) disconnects [a,b] while the circle remains connected upon removal of any point. More precisely, suppose that h: [a,b] is a homeomorphism. Choose a point x in (a,b), and consider X = [a,b] \ {x}. The restriction of h to X is a homeomorphism from X onto Y, where Y is the circle with one point, hx, removed. But X is disconnected, while Y is connected. Hence h can not exist and the segment is not homeomorphic to the circle.
 Example The circle is not homeomorphic to the figure eight. Removing any two points of the circle disconnects it, but this is not true of the figure eight. Or, removing the crossing point disconnects the figure eight, but removing no points disconnects the circle. pg 85 Pugh
What I don't understand is how M connected and N disconnected implies M, N not homeomorphic, as in the first example. If I take this as being true, I understand the logic of the second example, with the detailed explanation of the process of removing a point. However, I still don't see M connected and N disconnected implying M,N not homeomorphic.

Many thanks to anyone who can help me out.
P: 1,716
 Quote by rekovu I'm using Real Mathematical Analysis by Pugh to supplement my analysis class, and the book has been clear thus far, but I've been stuck for days on a concept I've had a hard time understanding. Just for reference, here is how a homeomorphism is defined: And here is how connectedness is defined: I understand that M connected and M homeomorphic to N implies N connected, and that M connected, f:M->N continuous, and f onto implies N connected. However, what I don't understand are examples such as the following: What I don't understand is how M connected and N disconnected implies M, N not homeomorphic, as in the first example. If I take this as being true, I understand the logic of the second example, with the detailed explanation of the process of removing a point. However, I still don't see M connected and N disconnected implying M,N not homeomorphic. Many thanks to anyone who can help me out.
homeomorphisms preserve open sets.
Mentor
P: 4,499
 Quote by rekovu I understand that M connected and M homeomorphic to N implies N connected, and that M connected, f:M->N continuous, and f onto implies N connected. However, what I don't understand are examples such as the following:
So if N is not connected, and a homeomorphism exists from M to N when M is connected, we get a contradiction (because N is connected and not connected at the same time)

P: 429

## Relationship b/w Connectedness and Homeomorphisms

 Quote by rekovu I understand that M connected and M homeomorphic to N implies N connected...
 Quote by rekovu What I don't understand is how M connected and N disconnected implies M, N not homeomorphic...
Your understanding of one should imply your understanding of the other!

 Related Discussions Calculus & Beyond Homework 0 Calculus 6 Calculus 4 Calculus & Beyond Homework 8 Calculus & Beyond Homework 9