How Can I Isolate the Variable K in a Math Equation?

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Discussion Overview

The discussion revolves around isolating the variable \( r \) in the equation \(-5r + 6 = 8\). Participants provide explanations and methods for solving this algebraic equation, focusing on the steps involved in manipulating the equation to isolate the variable.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant outlines the steps to isolate \( r \) by subtracting 6 from both sides and then dividing by -5, resulting in \( r = \frac{2}{-5} \).
  • Another participant emphasizes the importance of understanding the process and suggests seeking clarification if needed.
  • A different perspective introduces a conceptual analogy of balancing weights to explain the operations allowed in manipulating equations, such as adding or subtracting the same amount on both sides to maintain balance.

Areas of Agreement / Disagreement

Participants generally agree on the methods for isolating the variable, but there is no explicit consensus on the best approach or the clarity of explanations provided.

Contextual Notes

Some participants express varying levels of understanding and comfort with the material, indicating that additional clarification may be necessary for those struggling with the concepts.

Who May Find This Useful

This discussion may be useful for students seeking help with basic algebraic equations, particularly those in middle or high school mathematics.

dumb dumb
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k i am in grade 9 have a terrible math teacher and i need help with this stuff here is an example
-5r + 6 =8
so can u please explain to me how to exactly do this stuff.
THX
 
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[tex]-5r + 6 =8[/tex]

Well whatever you do on your equation you must do it on both sides of it.
to get r alone we could substract 6 from both sides so

[tex]-5r + 6 -6 =8 - 6[/tex]

[tex]-5r = 2[/tex]

Now could divide by -5 both sides.

[tex]r = \frac{2}{-5}[/tex]

there you go, was i clear enough?
 
One word of extra advice from someone who almost failed algebra: Make sure you get it the first time, but if not, ask your instructor, or even us, for clarification. But I see that you have done that already. Good luck!
 
dumb dumb:
Here's a way you ought to think about an equation:
Think of it as an old-fashioned weight which has two bowls attached to a rod with a fulcrum in the middle, and that that weight must stay in BALANCE all the time.
Such a weight would tip to one side if more weight was added to the bowl on that side than the other.
Hence, the only operations you're allowed to do is:
1.Add/subtract the same amount on both sides
(This would keep the weight in balance)
2.Multiply/divide with the same factor on both sides
This would also keep the weight in balance.
3. Substitute an equal amount to what's in ONE of the bowls:
For example, if you have:
2+3=4x+4, then you can, of course write this as 5=4x+4, since 2+3=5
 
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