# Linear Algebra: Orthonormal Basis

by tylerc1991
Tags: algebra, basis, linear, orthonormal
 P: 166 1. The problem statement, all variables and given/known data Find an orthonormal basis for the subspace of R^4 that is spanned by the vectors: (1,0,1,0), (1,1,1,0), (1,-1,0,1), (3,4,4,-1) 3. The attempt at a solution When I try to use the Gram-Schmidt process, I am getting (before normalization): (1,0,1,0), (0,1,0,0), (1,0,-1,2), (0,0,0,0). So obviously there is some mistake that I am making but I have checked this at least 3 times. Can someone help me and let me know if it is something on my end or the problem. Thank you.
 Sci Advisor HW Helper Thanks P: 25,228 Without have actually worked it out fully, why do you think you made a mistake? The dimension of the subspace is less than 4. You are only going to get a number of orthonormal vectors equal to the dimension of the subspace.
P: 166
 Quote by Dick Without have actually worked it out fully, why do you think you made a mistake? The dimension of the subspace is less than 4. You are only going to get a number of orthonormal vectors equal to the dimension of the subspace.
I thought that the basis had to span R^4? And since of of the elements was (0,0,0,0) the basis can't span R^4.

HW Helper
Thanks
P: 25,228
Linear Algebra: Orthonormal Basis

 Quote by tylerc1991 I thought that the basis had to span R^4? And since of of the elements was (0,0,0,0) the basis can't span R^4.
It doesn't span R^4. It spans the subspace of R^4 spanned by the given vectors.
P: 166
 Quote by Dick It doesn't span R^4. It spans the subspace of R^4 spanned by the given vectors.
I see. So will (0,0,0,0) be included in the orthonormal basis?