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Inverse Laplace Transform |
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| Apr20-11, 02:43 PM | #1 |
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Inverse Laplace Transform
The problem statement, all variables and given/known data
Find the inverse laplace transform of: 1/(s-2)3 + 25/(s+1)(s-2)2 + s/(s-2)2 The attempt at a solution I get (1/2)e2tt2 + (25/7)e-t-(25/7)e2t+(75/7)te2t for the first two, but I'm not even sure where to start for s/(s-2)2. I was thinking it might use convolution, but I'm not sure that I understand how convolution works... I'd really just like a hint to get me started on it... |
| Apr20-11, 02:54 PM | #2 |
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1/(s-2)2 looks like a shifted form of 1/s2, so you want to write numerator in terms of (s-2), i.e. s = (s-2)+2.
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| Apr20-11, 03:05 PM | #3 |
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Okay, so then I would have (s-2)/(s-2)2 + 2/(s-2)2
which is 1/(s-2) + 2/(s-2)2 so then I'd get e2t + 2e2tt |
| Apr20-11, 03:54 PM | #4 |
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Inverse Laplace Transform
That's right. You may want to check your algebra on your earlier work. Mathematica gets a different answer than you do.
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