Calculate EMF of Cell with 10 ohms & 15 ohms Resistors

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  • Thread starter Thread starter Chris-is-stuck
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SUMMARY

The discussion focuses on calculating the electromotive force (EMF) of a cell connected in series with a microammeter and two resistors of 10 ohms and 15 ohms. The total resistance in the circuit is determined to be 25 ohms. Given a current of 200 microamperes (uA), the EMF can be calculated using the formula EMF = iR, resulting in an EMF of 5 millivolts (mV).

PREREQUISITES
  • Understanding of Ohm's Law
  • Basic knowledge of electrical circuits
  • Familiarity with units of current (microamperes)
  • Concept of series circuits
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  • Learn about the characteristics of series and parallel circuits
  • Explore the concept of EMF in various types of cells and batteries
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Chris-is-stuck
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hi I am sorry this is probably going to seem very easy to all you viewers but up to this point I've had to teach myself physics because i had no teacher. i still got a* at gcse though :-p

the question is: A cell of negligible resistance is connected in a series with a microammeter of negligible resistance and two resistores of 10 ohms and 15 ohms. The current is 200 uA.

Calculate the EMF of the cell.

thanks a lot to anyone to helps me with this, cya later.


(jsut read rules sorry if I've broken any)
 
Last edited:
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The total resistance is R=10+15=25 ohms. Therefore:

EMF = iR

You have i, so...
 

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