Limits and choosing an epsilon properly?

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Homework Help Overview

The discussion revolves around a limit problem in calculus, specifically concerning the behavior of a function as it approaches a certain value. The original poster seeks assistance in demonstrating that if the limit of a function f(x) as x approaches c is greater than a constant K, then there exists a neighborhood around a point d where f(x) remains greater than K.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the definition of limits and the significance of choosing an appropriate epsilon in relation to the limit. There are inquiries about the relationship between the points c and d, as well as the implications of the limit being greater than K. Some participants suggest that understanding the epsilon-delta definition is crucial for tackling such problems.

Discussion Status

The conversation is ongoing, with various participants exploring different aspects of the problem. Some have provided hints regarding the epsilon-delta approach, while others express confusion about the concepts involved. There is no explicit consensus yet, but several productive lines of reasoning have been initiated.

Contextual Notes

Participants are grappling with the definitions and implications of epsilon and delta in the context of limits. There is a noted uncertainty regarding how to effectively choose epsilon to ensure that f(x) remains above K, as well as the relationship between the values of L and K.

matrix_204
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I really need help on solving this question:

Let d and K be given real numbers. Suppose that lim f(x) > K.
x->c
Show that there is a number h>0 such that f(x) > K for all x in the punctured open interval of width 2h centred at d.

The only hint that i was given was that if there are two real numbers as close as you like, then they are basically the same real.
How can i show this using this idea?
 
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Is c=d?
 
yes that is the idea, but how am i suppose to show that it's equal
 
Suppose [tex]\lim_{x\rightarrow c}f(x)=L>K[/tex]

Write down the definition of the limit in this case. There's a [tex]|f(x)-L|<\epsilon[/tex] part. This controls how close f is to L. By chosing epsilon properly, you can force f to be some distance away from any number not equal to L (on some punctured disc centered at c of course).

For example if you know [tex]|f(x)-L|<1/2[/tex] on some interval, then can [tex]f(x)=L+1/2[/tex] on this interval? Can it equal anything larger? What's the lowest it could be?
 
What does it mean when asking to chosing an epsilon properly?



Also, can someone clarify, how the graph of two horizontal lines work? i.e, y=L , y=f.
 
Last edited:
matrix_204 said:
What does it mean when asking to chosing an epsilon properly?

Also, can someone clarify, how the graph of two horizontal lines work? i.e, y=L , y=f.

You can think of epsilon as bounds for your function on the corresponding interval [tex]0<|x-c|<\delta[/tex].On this interval, your function will only take on values above [tex]L-\epsilon[/tex] and below [tex]L+\epsilon[/tex]. How do you pick epsilon to leave K out of this range? If epsilon is too large, you won't be able to rule out the possibility that f(x)=K.


Your horizontal lines..y=L would just be a horizontal line at height L, y=f won't necessarily be a horizontal line, f is a function. I don't think I understand your question.
 
So in order to show that f(x)> K for all x.. what are the main steps required in proving this, and also is there any techniques that can be used in solving delta-epsilon type of problems? I m really confused in these types of problems, i don't seem to understand the concept of delta and epsilon, like i kno that they are really small and can be regarded as equal, or not equal but very close, etc.
 
1) pick an [tex]\epsilon >0[/tex] so that if [tex]|f(x)-L|<\epsilon[/tex] you know [tex]|f(x)-K|>0[/tex]. Your particular epsilon will depend on how far L is from K.
2) Appeal to the definition of the limit to produce a [tex]\delta >0[/tex] so that if [tex]0<|x-c|<\delta[/tex] then [tex]|f(x)-L|<\epsilon[/tex]. You won't know what this delta is, but the fact that the limit is L guarantees it's existence.
3) Combine the above.

epsilon-delta type proofs are important if you want an understanding of calculus. Everything you do later on depends on limits, and without understanding epsilon-delta you won't rigorously understand what a limit is. You really need to work some examples and try to understand the definition of the limit as much as possible. Practice is important.
 

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