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Linear Algebra planes in 4d

by ctrlaltdel121
Tags: linear algebra, planes, vectors
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ctrlaltdel121
#1
May9-11, 09:44 PM
P: 1
1. The problem statement, all variables and given/known data

I am given two lines in vector form in 4-space. I need to write an equation for the plane that is parallel to one line, and contains the other line.


2. Relevant equations
well i know that in 3d I would find a normal vector for the plane that would be perpendicular to both lines, and that would let me define the plane. However i am stumped because in 4-space there are an infinite amount of vectors that are perpendicular to both lines.


3. The attempt at a solution
I took the dot product of the vectors and got an infinite number of possible normals. I know one point on the plane from the line that is contained in the plane, all i need is another vector in the plane to define it but I cannot figure it out.

I didn't want to give the numbers here because i can find it out on my own once I am given some direction.
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CompuChip
#2
May10-11, 12:22 AM
Sci Advisor
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Quote Quote by ctrlaltdel121 View Post
However i am stumped because in 4-space there are an infinite amount of vectors that are perpendicular to both lines.
The same is true in three dimensions: all the vectors (0, 0, z) for z not equal to 0 are perpendicular to the (x, y) plane.
In this case, the space of vectors which is perpendicular to both lines is just two-dimensional, instead of one. For example, for the (x, y) plane the perpendicular vectors would be (0, 0, z, u) for z.u not equal to 0.


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