Energy, Work and circular motion

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SUMMARY

The discussion focuses on solving two physics problems involving energy, work, and circular motion. The first problem involves determining the minimum angle theta for a pendulum to clear a peg without slack in the string, using the equation T + W = mv²/R, where T is tension and W is weight. The second problem addresses a box sliding down a frictionless ramp and colliding with a spring, requiring the use of conservation of energy to find the maximum velocity at spring compression. Key insights include the importance of energy conservation over speed calculations in these scenarios.

PREREQUISITES
  • Understanding of pendulum dynamics and circular motion
  • Familiarity with conservation of energy principles
  • Knowledge of basic trigonometry, particularly sine and cosine functions
  • Ability to differentiate functions to find maxima
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  • Study the principles of pendulum motion and energy conservation in circular motion
  • Learn how to apply conservation of energy in collision problems involving springs
  • Explore the use of derivatives in optimizing physical equations
  • Investigate the relationship between potential and kinetic energy in mechanical systems
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ok this first one is rated as a fairly tough problem.

1) A pendulum is formed from a small ball of mass m on a string of length L. As the figure shows, a peg is height h = L/3 above the pendulum's lowest point. From what minimum angle theta must the pendulum be released in order for the ball to go over the top of the peg without the string going slack?

http://s93755476.onlinehome.us/knight.Figure.10.54.jpg

so far i have set up the equation T + W = mv^2/R. since the tension of the rope is so that there is no slack, T = 0. so i get mv = mv^2/R and the masses cancel. for V, i found out that the minimum velocity is just sqrt(r*g). R = 2L/3 and h = L - Lcos(theta). however when i tried plugging all the data in, i get L-Lcos(theta) = 1/2*(2L/3). so then solving for theta i get arccos((2/3)*L/L) but when i try it, it says it doesn't depend on L or h. it wants the answer in degrees which i don't see how that's possible.
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2) A 23.0 kg box slides 4.0 m down the frictionless ramp shown in the figure, then collides with a spring whose spring constant is 150 N/m. At what compression of the spring does the box have its maximum velocity?

http://s93755476.onlinehome.us/knight.Figure.10.69.jpg

i know i have to take the derivative of something and set equal to 0 to find the maximum. but of what equation I am not sure.
 
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Let's look at 1)
You're very close
sin(a)=1/3L/L
a=arcsin(1/3)
Or in your case arccos(2/3)
You only missed that L/L=1 :P so the angle is arcsin(1/3)
 
Last edited:
Regarding problem #1:
quick said:
so far i have set up the equation T + W = mv^2/R. since the tension of the rope is so that there is no slack, T = 0. so i get mv = mv^2/R and the masses cancel. for V, i found out that the minimum velocity is just sqrt(r*g).
Right, but you'll have an easier time of it if you think in terms of energy, not speed.
R = 2L/3 and h = L - Lcos(theta). however when i tried plugging all the data in, i get L-Lcos(theta) = 1/2*(2L/3).
Now you lost me. For one, R = L/3. What does h need to be to give the mass its needed speed as it reaches the top of its motion? (Hint: What is the height of the mass at the top of the motion?)

Regarding problem #2:
i know i have to take the derivative of something and set equal to 0 to find the maximum. but of what equation I am not sure.
Use conservation of energy to get an expression for the kinetic energy as a function of spring compression. That's what you need to maximize.
 

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