Minimum Speed and Coefficient of Friction for a Car on a Circular Race Track

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SUMMARY

The discussion focuses on calculating the minimum speed and coefficient of friction required for a car to safely navigate a circular race track with a radius of 340 meters and a lateral acceleration of 1.2g. The maximum speed was determined to be 64.17 m/s, which converts to approximately 141.48 mi/hr. The necessary coefficient of friction to prevent sliding was calculated to be 1.24. These calculations are essential for ensuring vehicle stability on level, unbanked tracks.

PREREQUISITES
  • Understanding of circular motion dynamics
  • Familiarity with the formula for lateral acceleration (A=V^2/r)
  • Knowledge of friction coefficients and their significance in vehicle dynamics
  • Basic unit conversion skills (e.g., meters per second to miles per hour)
NEXT STEPS
  • Research the effects of track banking on vehicle dynamics
  • Explore advanced friction models for different tire compositions
  • Learn about vehicle stability control systems
  • Investigate the impact of weight distribution on cornering performance
USEFUL FOR

Automotive engineers, race car drivers, physics students, and anyone involved in vehicle dynamics and performance optimization.

Wi3rdtami
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I got a problem: let's say a car traveling around a circular race track of radius 340m. The lateral acceleration of the car is 1.2g. The roadway of the track is level, not banked. What is the mininum speed at which the car can travel on the track without rolling over? What is the minimum coefficient of friction needed between the tires and the roadway so the car will not slide out. I tried my best was unable to solved this one.
 
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What exactly did you try?
 
Well, I know how to solve it now.

First I found the max speed

A=V^2/r where v will equal 64.17 m/s

Change the units into mi/hr which would be 141.48 then plug it
Into mg= ma and get 1.24 as the coefficient of friction
 

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