Head-on Collision: 4.5 kg & 11 kg Objects

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SUMMARY

A 4.5 kg object traveling at 4.0 m/s collides head-on with an 11 kg object moving at 3.0 m/s, resulting in the 11 kg object coming to a complete stop. The final speed of the 4.5 kg object is calculated using the conservation of momentum, factoring in the direction of motion. The correct formula is (4.5 kg * 4.0 m/s) - (11 kg * 3.0 m/s) = (4.5 kg * Vf), leading to a final speed of 11.333 m/s. To determine if the collision is elastic, one must also check if the conservation of energy holds true.

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A 4.5 kg object with a speed of 4.0 m/s collides head-on with a 11 kg object moving toward it with a speed of 3.0 m/s. The 11 kg object stops dead after the collision.

(a) What is the final speed of the 4.5 kg object?
(b) Is the collision elastic?

so i tried initial momentum = final momentum but I get the wrong answer.
(4.5 kg)(4.0 m/s) + (11 kg)(3.0 m/s)=(4.5 kg)(Vf)
and solving for Vf = 11.333 m/s, but that is the wrong answer.
 
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Take into account that they have different directions. One momentum will be positive while the other negative.
 
Conservation of Momentum is the correct property to use, but you forgot to factor in that the two objects are moving at different directions before the collision, so initial momentum = 4.5kg * 4 m/s - 11kg * 3 m/s

For the second part, you should just see if Conservation of Energy is also upheld in the collision.

~Lyuokdea
 

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