11000=12184/9n co-efficient of friction?

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SUMMARY

The discussion centers on calculating the coefficient of friction (n) using the equation 11000 = 12184 / (9n). The user seeks clarification on rearranging the equation to isolate n. The solution involves multiplying both sides by n to yield 11000n = 12184 / 9, followed by dividing both sides by 11000 to derive n = 12184 / (9 * 11000). This straightforward algebraic manipulation effectively determines the coefficient of friction.

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EIRE2003
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I am just about to find the co-efficient of friction from my experimental results, and from the equation I can't get past this bit. how do I calculate the co-efficient of friction from or which way do I re-arrange the equation so I can find n, the co-efficient of friction?

11000=12184/9n

Silly question innit! :biggrin:
 
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[tex]11000=\frac{12184}{9n}[/tex]

Multiply both sides by n

[tex]11000n=\frac{12184}{9}[/tex]

Divide both sides by 11000

[tex]n=\frac{12184}{(9)(11000)}[/tex]
 
thanking you so much :biggrin:
 

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