How Far Can the Block Be Placed on a Rotating Turntable Without Sliding Off?

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SUMMARY

The maximum distance a brass block can be placed from the axis of a rotating turntable without sliding off is determined by the coefficient of friction (µ = 0.26) and the rotational speed (33 1/3 rev/min). The frictional force provides the necessary centripetal force to keep the block in place. The relationship between these forces is expressed as mgµ = mv²/r, leading to the formula gµ = v²/r. By substituting v with r multiplied by the rotational speed, one can calculate the critical radius before sliding occurs.

PREREQUISITES
  • Understanding of centripetal force and its relation to circular motion
  • Knowledge of friction coefficients and their impact on motion
  • Familiarity with basic physics equations, particularly F = ma
  • Ability to convert rotational speed from revolutions per minute to linear velocity
NEXT STEPS
  • Calculate the maximum radius for different coefficients of friction
  • Explore the effects of varying rotational speeds on sliding thresholds
  • Learn about the dynamics of rotating systems in physics
  • Investigate real-world applications of friction in engineering design
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Physics students, mechanical engineers, and anyone interested in the dynamics of rotating systems and frictional forces.

siralan
The coefficient of friction between a certain brass block and a large revolving turntable is µ = 0.26. How far from the axis of rotation can the block be placed before it slides off the turntable if it is rotating at 33 1/3 rev/min?

:confused: :frown: :smile:
 
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Consider that it is friction that supplies the centripetal force.
 
As long as the force that is needed to overcome friction is larger than the centripetal force the block will not move.

[tex]F_{friction} = F_z \mu = mg\mu[/tex]
[tex]F_{centripetal} = \frac{mv^2}{r}[/tex]

so you can move the block from the axis of rotation until these are equal, and when they are equal this holds:
[tex]mg\mu = \frac{mv^2}{r} \Leftrightarrow g\mu = \frac{v^2}{r}[/tex]
and using [itex]v = r*v_{rotational}[/itex] you can solve this
 

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