Understanding the Limit of Sin7x/4x as x Approaches 0

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SUMMARY

The limit of sin(7x)/4x as x approaches 0 is evaluated using the fundamental limit property that states lim x→0 (sin x)/x = 1. By substituting 7x for x in this property, we find that lim x→0 (sin(7x))/(7x) = 1. Consequently, the limit can be expressed as lim x→0 (sin(7x)/4x) = (7/4) * lim x→0 (sin(7x)/(7x)) = 7/4.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with trigonometric functions
  • Knowledge of the limit property lim x→0 (sin x)/x = 1
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the derivation of the limit property lim x→0 (sin x)/x = 1
  • Explore L'Hôpital's Rule for evaluating indeterminate forms
  • Learn about Taylor series expansions for trigonometric functions
  • Investigate the application of limits in real-world scenarios
USEFUL FOR

Students studying calculus, educators teaching limit concepts, and anyone looking to deepen their understanding of trigonometric limits.

Coldie
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You're asked to find lim x-->0 sin7x / 4x

The part of this example that I don't understand the most is how they get 1 out of sin7x/7x when x-->0.

[edit]
Sorry about the ridiculously small image. The dimension restrictions are ridiculous, and I didn't notice that the image didn't attach properly the first time.
[/edit]
 

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Are you familiar with [itex]\lim_{x \rightarrow 0} (sin x) / x = 1[/itex]?
 
No, I was not. I guess that clears that up, thanks:p
 

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