# How do I find the distance traveled if I know the acceleration and time?

by vbman11
Tags: acceleration, distance, time, traveled
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 P: 5 so if A is the acceleration and T is time and D is distance then D = A * T^2 right????
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P: 40,932
 Quote by vbman11 so if A is the acceleration and T is time and D is distance then D = A * T^2 right????
Here's a good intro for you:

http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

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P: 5
 Quote by berkeman Here's a good intro for you: http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html .
I was looking for a quick check to make sure i'm right... so yes or no?

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How do I find the distance traveled if I know the acceleration and time?

 Quote by vbman11 I was looking for a quick check to make sure i'm right... so yes or no?
Please look at the link. The answer is right there in a big box on the front page.
 P: 5 Sry bud you just sent me a link to a page that contains an HTML frame. go ahead and try that link out for yourself and see. It'll just show the home page.
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P: 40,932
 Quote by vbman11 Sry bud you just sent me a link to a page that contains an HTML frame. go ahead and try that link out for yourself and see. It'll just show the home page.
Oopsies. I didn't realize the link didn't follow me down a couple of click levels. I'll have to figure out how to fix that.

In the mean time, just click on Mechanics, and then on Velocity & Acceleration.

Does that work okay?
P: 143
 Quote by vbman11 so if A is the acceleration and T is time and D is distance then D = A * T^2 right????
Nope, it's (A *T^2 )/2

So 9 seconds and 32 f/s (1g) would cover about one quarter mile, 1320 feet.
32*81=2592, divide by 2=1296 feet. A true quarter mile would be about 9.08 seconds.

73 Berkeman, AI3N here. 2 meters, 70 cm, 20/30/40/80 voice mainly. Antenna blew down, need one of those air powered potato guns to get the dipole back in the trees!

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