Electricity Q: Current in Circuit w/ 8V DC?

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SUMMARY

The discussion centers on the behavior of current in a direct current (DC) circuit powered by an 8V supply. It is established that the current is not constant and varies with changes in resistance, as described by Ohm's Law (I = V/R). The presence of a variable resistor allows for adjustments in resistance, directly affecting the current measured by an ideal ammeter. This relationship confirms that in a series circuit, as resistance increases, the current decreases proportionally.

PREREQUISITES
  • Understanding of Ohm's Law (I = V/R)
  • Familiarity with basic electrical components: ammeter, lightbulb, variable resistor
  • Knowledge of series circuit configurations
  • Basic principles of direct current (DC) electricity
NEXT STEPS
  • Study the implications of Ohm's Law in different circuit configurations
  • Explore the functionality and applications of variable resistors in circuits
  • Learn about the characteristics of ideal vs. real ammeters
  • Investigate the effects of voltage changes on current in DC circuits
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Electronics students, hobbyists experimenting with circuits, and anyone seeking to understand the principles of current flow in DC electrical systems.

Karate Chop
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Just a simple question, if u have an electric circuit that has a DC power supply, and you set it to 8 volts, u have an ammeter, lightbulb and variable resistor also in the circuit, does the current in the circuit change as the resistance changes, or is the current always constant?
 
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i am not sure but due to the fact that you have a variable resistor and the ammeter is ideal, the current isn't constant. i think it is related to Ohm's law:
I=V/R
 
For a series circuit, the relationship between voltage (V) and current (I) is given by V = IR, where R is the total resistance. So if you change the resistance, the current will change accordingly.
 

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