|Jul23-11, 06:35 AM||#1|
Ok, so I have uploaded/attached the question and the solution. I just need help understanding the solution please. I understand how to calculate the initial inverse transform, but I included it as the reference to the second part of the question regarding the y'' + 4y' = H(t-3)
Can someone please explain the full steps to invert the laplace transform Y to f, like the solution shows in the last step?
I have got to the following point, but I think I may be forgetting some Laplace Transform identities needed to make my life easier?
I can split the equation into parts where I recognise a few Laplace Transforms but not sure about the rest, cheers...
Y(s) = (1/s).e-3s.[1/(s2+22)] + [s/(s2+22)] - [2/s2+22]
I recognise a few inverse laplace transforms there but without adding my confusion to the mess can someone please clarify how they got the answer? many thanks in advance.
hopefully I didnt make this post toooo convoluted with my thoughts!
|Jul23-11, 11:48 AM||#2|
U are confused because they have skipped a step.
I bet u must have recognised this part: [s/(s2+22)] - [2/s2+22]
For this part: (1/s).e-3s.[1/(s2+22)] :
|Jul23-11, 12:27 PM||#3|
How did you get rid of the e^(-3s) ?
thanks for helping.
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