Max Speed for 0.20kg Mass on Rotating Turntable

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SUMMARY

The maximum speed of a 0.20 kg metal cylinder on a rotating turntable can be calculated using the relationship between centrifugal force and static friction. Given a coefficient of static friction of 0.080 and a radius of 0.15 m from the center, the static friction force must equal the required centripetal force. The equation used is mass multiplied by angular velocity squared times the radius equals the static friction force, which is derived from the normal force and the coefficient of friction.

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  • Understanding of centrifugal force and centripetal acceleration
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  • Familiarity with basic physics equations involving mass and rotation
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tigerseye
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I need help with this one problem:
A small metal cylinder rests on near the edge of a circular turntable that is rotating at a constant speed. The small metal cylinder has a mass of 0.20 kg, the coefficient of static friction between the cylinder and the turntable is 0.080, and the cylinder is located 0.15 m from the center of the turntable.
What is the maximum speed that the cylinder can move along its circular path without slipping off the turntable?
 
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Centrifugal force = Force due to static friction
Centrifugal force = mass*omega^2*radius
Static Force = normal force * mju
normal force = weight
mju = 0.080
equate for omega
:)
 
Static friction must provide the centripetal acceleration of the cylinder.
 

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