Need Torque Help! Calculate Force on Pillars Supporting Tabletop

  • Thread starter Thread starter JeanneM24
  • Start date Start date
  • Tags Tags
    Torque
Click For Summary
SUMMARY

The discussion focuses on calculating the forces exerted on pillars supporting a 4.5m long tabletop with a mass of 30kg, when a 210lb (95.25kg) man sits at one end. The total weight on the pillars is 125.25kg, resulting in a torque of 281.81 N*m when calculated from the center pivot point. Each pillar experiences a torque of 140.90 N*m, leading to a force of approximately 140.90 N on each pillar. This calculation is essential for understanding the load distribution on the supporting structures.

PREREQUISITES
  • Understanding of torque calculations (T = F * d)
  • Knowledge of unit conversions (pounds to kilograms)
  • Familiarity with basic physics concepts related to forces and moments
  • Ability to identify pivot points in static systems
NEXT STEPS
  • Research "Torque calculations in static equilibrium" for deeper insights
  • Learn about "Unit conversion techniques for weight measurements" to avoid common pitfalls
  • Explore "Applications of torque in engineering structures" for practical examples
  • Study "Load distribution in beam supports" to understand broader implications
USEFUL FOR

Students in physics or engineering, structural engineers, and anyone involved in designing or analyzing load-bearing structures will benefit from this discussion.

JeanneM24
Messages
2
Reaction score
0
Need Torque help!

I don't understand or even know where to start with this problem:

A uniform 4.5m long tabletop is supported by pillars 1 meter on each side of the center of the tabletop. The tabletop has a mass of 30kg. A 210lb man sits on one end of the table. Find the force of each of the pillars.

Can anyone help?
 
Physics news on Phys.org
First, you need to pick a reference point (I'd recommend one of the ends of the table). Then, you need to calculate the downward forces and torque on the object, and from there you can find the forces of the two pillars. Also, be weary of your units on this problem.
 


Sure, I can help you with this problem. To calculate the force on each pillar, we first need to find the torque exerted by the tabletop and the man on the pillars. Torque is the force applied at a distance from a pivot point, and it is expressed as T = F * d, where T is the torque, F is the force, and d is the distance from the pivot point.

In this case, the pivot point is the center of the tabletop, and the force is the weight of the tabletop and the man. Since the tabletop has a mass of 30kg and the man weighs 210lbs, we need to convert the weight of the man to kilograms. 210lbs is equivalent to 95.25kg. So, the total weight of the tabletop and the man is 30kg + 95.25kg = 125.25kg.

Now, we need to find the distance from the pivot point to the end of the tabletop where the man is sitting. This distance is half the length of the tabletop, which is 2.25m. Therefore, the torque exerted by the tabletop and the man is T = (125.25kg) * (2.25m) = 281.81 N*m.

Since there are two pillars supporting the tabletop, the torque will be divided between them. This means that each pillar will experience a torque of 281.81 N*m / 2 = 140.90 N*m.

To find the force on each pillar, we can use the formula T = F * d and rearrange it to solve for F. We know the torque (140.90 N*m) and the distance from the pivot point to the pillar (1m), so we can plug these values in to find the force.

F = T / d = (140.90 N*m) / (1m) = 140.90 N

Therefore, the force on each pillar is approximately 140.90 N. I hope this helps you in solving your problem. Let me know if you have any further questions.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
2K
Replies
6
Views
3K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 25 ·
Replies
25
Views
3K
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K