Solving Film Projection & Telescope Questions

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SUMMARY

This discussion addresses two specific optical problems: calculating the focal length of a projection lens for a film projection apparatus and determining the focal lengths of the objective and eyepiece lenses in an astronomical telescope. For the film projection, the focal length required is approximately 456 ft, derived from the magnification formula M = d/D = f/F. In the case of the telescope, the eyepiece focal length is calculated to be 1.6 in, leading to an objective lens focal length of approximately 25.6 in, using the magnification formula M = f/fe and the relationship f = fe + d.

PREREQUISITES
  • Understanding of optical magnification formulas
  • Familiarity with basic lens equations
  • Knowledge of film projection mechanics
  • Concept of focal length in optics
NEXT STEPS
  • Research the lens maker's equation for more complex lens designs
  • Explore the principles of optical magnification in detail
  • Learn about different types of projection systems and their applications
  • Investigate the design and function of telescopes, focusing on different types of eyepieces
USEFUL FOR

Students in optics, physics enthusiasts, and professionals involved in film projection and telescope design will benefit from this discussion.

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URGENT Can you please help!

Hello,

I have just finished what seems like an infinite amount of questions for this lab report. 2 of them I am just not sure how to proceed. Any help would be appreciated.

Question 1:
In a film projection apparatus, it is desired to produce pictures 12 ft wide on a screen 50 ft from the lens. The size of the picture on the film is 1 in. wide. What must be the focal length of the projection lens used?

Question 2:
The magnifying power of an astronomical telescope 24 in. long is equal to 15. Determine the focal length of the objective lens and that of the eyepiece. Assume the telescope is focused on a distant object.

Thank you.
 
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Hello there,

I can definitely assist you with these questions. For question 1, we can use the formula: M = d/D = f/F, where M is the magnification, d is the distance between the lens and the film, D is the distance between the lens and the screen, f is the focal length of the lens, and F is the distance between the film and the screen. We know that M = 12 ft/1 in. = 144 in., D = 50 ft, and F = 50 ft - 12 ft = 38 ft. Plugging these values into the formula, we get: 144 = f/38, which gives us a focal length of 5472 in. or 456 ft. So, the focal length of the projection lens should be approximately 456 ft.

For question 2, we can use the formula: M = f/fe, where M is the magnification, f is the focal length of the objective lens, and fe is the focal length of the eyepiece. We know that M = 15 and f = 24 in. Plugging these values into the formula, we get: 15 = 24/fe, which gives us a focal length of the eyepiece of 1.6 in. To find the focal length of the objective lens, we can use the formula: f = fe + d, where d is the distance between the two lenses. We know that d = 24 in. and fe = 1.6 in. Plugging these values into the formula, we get: f = 24 + 1.6 = 25.6 in. So, the focal length of the objective lens should be approximately 25.6 in.

I hope this helps! Let me know if you have any further questions or need clarification on any steps. Good luck with your lab report!
 

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