Conservation of Energy and satellite

Click For Summary

Homework Help Overview

The discussion revolves around a problem in classical mechanics, specifically focusing on the conservation of energy and angular momentum in the context of a satellite's motion around a spherical planet. The original poster presents an attempt to derive the initial speed required for a satellite to reach a certain distance from the planet's center.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation laws, with one questioning the correctness of the original poster's calculations. There is a suggestion to derive two equations based on energy and angular momentum principles to solve for the unknowns.

Discussion Status

The conversation is ongoing, with participants providing guidance on the approach to take. There is recognition that the original poster needs to clarify their calculations and possibly revisit their understanding of the problem setup.

Contextual Notes

Participants note that the satellite's speed at its maximum distance is not zero, which is a critical aspect of the problem. There is also an acknowledgment of the need to solve for two unknowns, indicating a level of complexity in the equations involved.

phy
Imagine a spherical, nonrotating planet of mass M, radius R, that has no atmosphere. A satellite is fired from the surface of the planet with speed vo at 30 degrees to the local vertical. In its subsequent orbit the satellite reaches a maximal distance of 5R/2 from the center of the planet. Using the principles of conservation of energy and angular momentum, show that vo - (5GM/4R)^1/2


This is what I've done so far and it's not right:

E=1/2 mv^2 - GMm/2R = GMm/4R
1/2mv^2-GMm/2(5R/2) = GMm/4(5R/2)
1/2mv^2-GMm/5R = 2GMm/20R
1/2v^2 = 3GM/10R
.:v = (3GM/5R)^1/2

Clearly, this isn't the answer I should be getting. Does anybody know where I'm going wrong?
 
Physics news on Phys.org
phy said:
E=1/2 mv^2 - GMm/2R = GMm/4R
1/2mv^2-GMm/2(5R/2) = GMm/4(5R/2)
1/2mv^2-GMm/5R = 2GMm/20R
1/2v^2 = 3GM/10R
.:v = (3GM/5R)^1/2
I can't quite follow what you are doing. Apply conservation of energy to get one equation and conservation of angular momentum to get another. (I trust you realize that at the maximal distance, the speed is not zero.)
 
So I'm just going to be solving a system of 2 linear equations for 2 unknowns?
 
phy said:
So I'm just going to be solving a system of 2 linear equations for 2 unknowns?
I wouldn't call them linear... but, yes, you'll have two equations and two unknowns.
 
Oh yeah my bad. I meant just two equations. Ok thanks for that. I guess I'll redo the question and get back to you on that one. Thanks again.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
Replies
1
Views
2K
Replies
6
Views
2K
Replies
8
Views
4K
Replies
15
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K